Answer:
480 cm ^ 2
Step-by-step explanation:
To calculate the surface area of the figure, we must calculate the surface area of the cube, we know that they are identical, therefore, calculating the area of one is sufficient.
We have that the surface area of a cube is:
A = 6 * a ^ 2
where a is the edge, we know that if it is a cube all its sides are equal, in this case it is 4 centimeters, if we replace we have:
A = 6 * (4 ^ 2)
A = 96
96 square centimeters is the area of a cube, but since the area of the object would be the sum of the area of all the cubes, then:
AT = 96 * 5
AT = 480 cm ^ 2
The surface area of the object formed with the cubes is 480 cm ^ 2
Answer:
-7 < -3 because -7 is located to the left of -3 on a number line.
Step-by-step explanation:
This is because -7 is on the left of the -3. In negatives -3 is greater than -7. If it was positive then 7 would be greater than 3. So the answer is A. -7 < -3 because -7 is located to the left of -3 on a number line
As x heads off to negative infinity (towards the left side), the curve slowly approaches the horizontal line y = 1. It will never actually touch or cross this horizontal line. It simply gets closer and closer. Think of it as an electric fence of sorts.
Therefore the horizontal asymptote is y = 1
Answer:
x = -2
y = -1
(-2, -1)
General Formulas and Concepts:
<u>Pre-Algebra</u>
- Order of Operations: BPEMDAS
- Equality Properties
<u>Algebra I</u>
- Solving systems of equations using substitution/elimination
- Solving systems of equations by graphing
Step-by-step explanation:
<u>Step 1: Define systems</u>
y = x + 1
3x + 3y = -9
<u>Step 2: Solve for </u><em><u>x</u></em>
<em>Substitution</em>
- Substitute in <em>y</em>: 3x + 3(x + 1) = -9
- Distribute 3: 3x + 3x + 3 = -9
- Combine like terms: 6x + 3 = -9
- Isolate <em>x</em> term: 6x = -12
- Isolate <em>x</em>: x = -2
<u>Step 3: Solve for </u><em><u>y</u></em>
- Define original equation: y = x + 1
- Substitute in <em>x</em>: y = -2 + 1
- Add: y = -1
<u>Step 4: Graph systems</u>
<em>Check the solution set.</em>