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GenaCL600 [577]
3 years ago
10

-15 + 12x = 5x + 7 -3x SOLVE FOR X

Mathematics
2 answers:
tino4ka555 [31]3 years ago
7 0

Answer:

x = 2.2

Step-by-step explanation:

- 15 + 12x = 5x + 7 - 3x \\  + 12x - 5x + 3x = 15 + 7 \\ 10x = 22 \\  \frac{10x}{10}  =  \frac{22}{10}  \\ x = 2.2

Natali [406]3 years ago
6 0

Answer: x=\frac{11}{5}

<u>Simplify both sides of the equation</u>

<u></u>-15+12x=5x+7+-3x<u></u>

<u></u>12x-15=(5x+-3x)+(7) (Combine Like Terms)

12x-15=2x+7

<u>Subtract 2x from both sides</u>

<u></u>12x-15-2x=2x+7-2x\\10x-15=7<u></u>

<u></u>

<u>Divide both sides by 10</u>

<u></u>\frac{10x}{10} =\frac{22}{10}<u></u>

<u></u>x=\frac{11}{5}<u></u>

<u></u>

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This is a ratio problem; the ratio of the length to width is constant (and therefore equal):

4 /6 = 15 / x

Now, with a ratio, we may do any allowable algebra operation: cross-multiply, invert both sides, multiply or divide both sides by the same amount, etc.

Let's cross-multiply:

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3 years ago
How many pounds of mixed nuts that contain 70% peanuts must Shannon add to 15 pounds of mixed peanuts that contain 20% peanuts t
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Answer:

10 pounds.

Step-by-step explanation:

Let x pounds be the amount of mixed nuts we require.

Amount of peanuts in this mix = 0.70x pounds. Amount of peanuts in the 20% mix = 0.20*15 = 3 pounds.

So we have the equation:-

0.70 x + 3 = 0.40(x + 15)

0.70 x + 3 = 0.40(x + 15)

0.70x + 3 = 0.40x + 6

0.70x - 0.40x = 6 - 3

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3 years ago
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3 years ago
He dimensions are tripled. The new surface area would be times larger than the original surface area.
ddd [48]

Answer:

The new surface area would be 9 times larger than the original surface area.

Step-by-step explanation:

Here we do not know what was the original shape, but we will see that it does not matter.

Let's start with a square of side length L.

The original area of this square will be:

A = L^2

Now if each dimension is tripled, then all the sides of the square now will be equal to 3*L

Then the new area of the square is:

A' = (3*L)^2 = (3*L)*(3*L) = 9*L^2 = 9*A

So the new surface area is 9 times the original one.

Now, if the figure was a circle instead of a square?

For a circle of radius R, the area is:

A = pi*R^2

where pi = 3.14

Now if the dimensions of the circle are tripled, the new radius will be 3*R

Then the new area of the circle is:

A' = pi*(3*R)^2 = pi*9*R^2 = 9*(pi*R^2) = 9*A

Again, the new area is 9 times the original one.

If the figure is a triangle?

We know that for a triangle of base B and height H, the area is:

A = B*H/2

If we triple each measure, we will have a base 3*B and a height 3*H

Then the new area is:

A' = (3*B)*(3*H)/2 = (3*3)*(B*H/2) = 9*(B*H/2) = 9*A

Again, the new area is 9 times the original area.

So we can conclude that for any shape, the new area will be 9 times the original area.

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