Answer:
69% Ag, 10.5% S, 20.5% O.
Explanation:
Ag₂SO₄ → Molar mass = 311.8 g/mol
2 mol of Ag → 107.87g/m . 2m = 215.74 g
1 mol of S → 32.06g/m . 1m = 32.06 g
4 mol of O → 16g/m .4m = 64 g
Percentage composition will be:
(Mass of Ag/ Total mass) . 100
(215.74 g / 311.8 g) . 100 = 69 %
(Mass of S/ Total mass) . 100
(32.06 g / 311.8 g) .100 = 10.5%
(Mass of O/ Total mass) . 100
(64 g / 311.8 g) . 100 = 20.5 %
