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kicyunya [14]
2 years ago
8

9. Calculate the percentage composition of silver sulfate, Ag2SO4.

Chemistry
1 answer:
riadik2000 [5.3K]2 years ago
7 0

Answer:

69% Ag, 10.5% S, 20.5% O.

Explanation:

Ag₂SO₄ → Molar mass = 311.8 g/mol

2 mol of Ag → 107.87g/m . 2m = 215.74 g

1 mol of S → 32.06g/m . 1m = 32.06 g

4 mol of O → 16g/m  .4m = 64 g

Percentage composition will be:

(Mass of Ag/ Total mass) . 100

(215.74 g / 311.8 g) . 100 = 69 %

(Mass of S/ Total mass) . 100

(32.06 g / 311.8 g) .100 = 10.5%

(Mass of O/ Total mass) . 100

(64 g / 311.8 g) . 100 = 20.5 %

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Consider an exceptionally weak acid, HA, with a Ka = 1x10 -20 . You make a 0.1M solution of the salt Na
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Answer:

pH=13

Explanation:

Hello,

In this case, given the acid, we can suppose a simple dissociation as:

HA\rightleftharpoons H^+ + A^-

Which occurs in aqueous phase, therefore, the law of mass action is written by:

Ka=\frac{[H^+][A^-]}{[HA]}

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But we prefer to compute the Kb due to its exceptional weakness:

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Next, the acid dissociation in the presence of the base we have:

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Whose solution is x=0.0999M which equals the concentration of hydroxyl in the solution, thus we compute the pOH:

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Hope this helped!

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the input force would be 75 N

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The correct answer is A. The conservationist credited with founding the Wilderness Society is Bob Marshall.

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