All categories

3 years ago

Which one of the following statements best describes a solution with a pH of 3?

1 answer:

6 0

Statement D is the correct option as the solution will have pH of 3. It has an H3O+ ion concentration of 1 × $10^{-3}$ mol/L and is acidic.

Explanation:

It is given in question that solution must have pH of 3. The value if being less than 7 shows that solution is acidic. The pH value of 3 indicates that given solution is highly acidic and has strong acid. Strong acid gets fully dissociated into $H_{3}$ $O^{+}$ ions.

pH of the solution is calculated as:

pH = -log10[ $H_{3}$ $O^{+}$ ]

the concentration or molarity of the hydronium ion is given as moles/litre

concentration of hydronium ion in the solution is 1 X $10^{-3}$ moles/litre

putting the values in the equation:

pH = - log10( 1 X $10^{-3}$ )

pH = 3 (acidic)

Thus it can be concluded that D option is the right answer.

You might be interested in

How is ethanol different from carbon dioxide?

ira [324]

Answer:

Explanation:

Ethanol is C2H6O. Carbon diozidex is CO2. Ethanol has hydgrogen, where carbon dioxide does not.

6 0

3 years ago

Read 2 more answers

Show your work. 37.2 moles CO2 to oxygen atoms.

Rufina [12.5K]

4 moles of oxygen (6.0zzx10

4 0

3 years ago

Balance this equation-<br> _P4 + _02 --> _P203

ikadub [295]

Answer:

Explanation:

If you insist on filling in the first blank you can put a one.

3 0

3 years ago

How could measuring the melting point of a solid help decide whether it was a mixture or a compound?

mars1129 [50]

Answer: It can't.

Explanation:

In most cases, the melting point alone will not enable you to identify a compound. Millions of solid organic compounds, and their melting points, are known. Perhaps 10,000 of these will have the same melting point as your unknown compound.

Hope this helps!

8 0

3 years ago

Using the data, which of the following is the rate constant for the rearrangement of methyl isonitrile at 320 °C? (HINT: the act

algol13

Answer:

D) 2.3 x 10⁻¹ s⁻¹

Explanation:

The rate constant is related to the activation energy through the formula:

k= Ae^(-Eₐ /RT)

where A is the collision factor, Eₐ the activation energy, R is the gas constant ( 8.314 J/Kmol ) , and T is the temperature (K)

So a plot of lnk versus 1/T ( Arrehenius plot ) gives us a straight line with slope equal -Eₐ/R and intercept lnA

lnk = -(Eₐ/T)(1/T) + lnA

which has the form y= mx + b

In this problem, we can use the data provided to:

a) Using a calculator determine the slope and intercept and then calculate the value of rate constant at 320 ºC, or

b) Plot the data and determine the equation of the best line , and answer the question for k @ 320 ºC by reading the value from the plot.

Once you do the plot, the resulting equation is:

y = - 19 x 10³ x + 30,582 ( R² = 0.999 )

So for T = 320 + 273 K = 593 K

Y = 19 x 10³ X + 30.58

So for T = (320 + 273)K = 593 K

Y = -19 x 10³ ( 1/593) + 30.58 = -32.04 +30.58 = - 1.46

and then since

y = lnk ⇒ e^y = k

k= e^-1.46 = 2.3 x 10⁻¹ s⁻¹

Note: there is an error of transcription in the value for T = 472.1 ( 1/T = 2.118 x 10⁻³ and not 2.228 x 10⁻³). You can recognize this mistake if you plot the data and notice it produces an outlier.

5 0

3 years ago