A similar experiment was used to determine the empirical formula of an oxide of tin (Sn). Use the data provided to answer the fo
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<u>Answer:</u> The percent yield of the reaction is 68.68%.
<u>Explanation:</u>
To calculate the mass of salicylamide, we use the equation:
Density of salicylamide = 1.06 g/mL
Volume of salicylamide = 3.65 mL
Putting values in above equation, we get:
To calculate the number of moles, we use the equation:
.....(1)
Given mass of salicylamide = 3.869 g
Molar mass of salicylamide = 137.14 g/mol
Putting values in equation 1, we get:
The chemical equation for the conversion of salicylamide to iodo-salicylamide follows:
By Stoichiometry of the reaction:
1 mole of salicylamide produces 1 mole of iodo-salicylamide
So, 0.0295 moles of salicylamide will produce = of iodo-salicylamide
Now, calculating the mass of iodo-salicylamide from equation 1, we get:
Molar mass of iodo-salicylamide = 263 g/mol
Moles of iodo-salicylamide = 0.0295 moles
Putting values in equation 1, we get:
To calculate the percentage yield of iodo-salicylamide, we use the equation:
Experimental yield of iodo-salicylamide = 5.33 g
Theoretical yield of iodo-salicylamide = 7.76 g
Putting values in above equation, we get:
Hence, the percent yield of the reaction is 68.68%.