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3 years ago

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A similar experiment was used to determine the empirical formula of an oxide of tin (Sn). Use the data provided to answer the fo

llowing question. Calculate the number of moles of oxygen in the oxide of tin sample. 0.0356 moles 0.131 moles 0.167 moles

1 answer:

zzz [600]3 years ago

7 0

Yes you know do that two times

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lana66690 [7]

Answer:

c

Explanation:

3 0

3 years ago

Read 2 more answers

Sewage and industrial pollutants dumped into a body of water can reduce the dissolved oxygen concentration and adversely affect

MArishka [77]

Answer:

FALSE

Since 0.385 < 0.526, the value for week 3 is accepted.

Explanation:

Qexp = (|Xq - Xₙ₋₁|)/w

where Xq is the suspected outlier; Xₙ₋₁ is the next nearest data point; w is the range of data

First, the data are arranged in decreasing order, from highest to lowest:

3. 5.6

2. 5.1

8. 5.1

1. 4.9

6. 4.9

5. 4.7

7. 4.5

4. 4.3

Xq = 5.6; Xₙ₋₁ = 5.1; w = 5.6 - 4.3 = 1.3

Qexp = (|5.6 - 5.1|)/1.3 = 0.385

From tables, at 95% confidence level, for n = 8, Qcrit = 0.526

Since 0.385 < 0.526, the value for week 3 is accepted.

7 0

3 years ago

What pressure is exerted by 932.3 g of CH4 in a 0.560 L steel container at 136.2 K?

Roman55 [17]

Molar mass CH4 = 16.0 g/mol

* number of moles:

932.3 / 16 => 58.26875 moles

T = 136.2 K

V = 0.560 L

P = ?

R = 0.082

Use the clapeyron equation:

P x V = n x R x T

P x 0.560 = 58.26875 x 0.082 x 136.2

P x 0.560 = 650.76

P = 650.76 / 0.560

P = 1162.07 atm

5 0

3 years ago

Which of the following statements are correct regarding the binding energy?

Andrews [41]

None of the above?
(Is there any statements?)

8 0

3 years ago

HRISTINA HERRERA: Attempt 1

Lunna [17]

Answer:

7.5 g of hydrogen gas reacts with 50.0 g oxygen gas to form 57.5 g of water.

Explanation:

Here we have the check if the mass of the reactants is equal to the mass of the products.

Reactants

$7.5+50=57.5\ \text{g}$

Products

$57.5\ \text{g}$

The data is consistent with the law of conservation of matter.

Reactants

$50+243=293\ \text{g}$

Products

$206+97=303\ \text{g}$

The data is not consistent with the law of conservation of matter.

Reactant

$17.7+34.7=52.4\ \text{g}$

Products

$62.4\ \text{g}$

The data is not consistent with the law of conservation of matter.

Only the first data is consistent with the law of conservation of matter.

8 0

3 years ago