The volume of the pyramid with the given length, width and height is 165in³.
<h3>What is the volume of the pyramid?</h3>
The volume of a right rectangular pyramid is expressed as;
V = ( L × W × H ) / 3
Given that;
- Length L = 11in
- Width W = 9in
- Height H = 5in
We substitute into the equation above.
V = ( L × W × H ) / 3
V = ( 11in × 9in × 5in ) / 3
V = 495in³ / 3
V = 165in³
The volume of the pyramid with the given length, width and height is 165in³.
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6*2=12
32-12=20
20/2=10.
Perimeter is all the way around an object. So take 6 two times and minus that from 32. Answer of that divide by 2 to get the length. Length of one side is 10 ft.
Answer:
−(7p+6)−2(−1−2p) = - 3p - 4
Step-by-step explanation:
−(7p+6)−2(−1−2p) = -7p - 6 + 2 + 4p
= (-7p + 4p) + (2 - 6)
= -(7p - 4p) - (6 - 2)
= - 3p - 4
Answer:
A
Step-by-step explanation:
Given
f(x) = 
The denominator of f(x) cannot be zero as this would make f(x) undefined.
Equating the denominator to zero and solving gives the value that x cannot be and if the numerator is non zero for this value then it is a vertical asymptote.
x + 3 = 0 → x = - 3 is the vertical asymptote
Answer:
x = 15
Step-by-step explanation:
y = family members = 7
x = cost of ticket
7x + 6y = 147
Substitute 7 for y:
7x + 6(7) = 147
7x + 42 = 147
Subtract 42 on both sides:
7x + 42 = 147
- 42 -42
7x = 105
Divide both sides by 7:
7x = 105
x = 15
