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stiv31 [10]
3 years ago
14

A compounds empirical formula is CH2. If the formula mass is 28 g/mol, what is the molecular formula

Chemistry
1 answer:
AleksAgata [21]3 years ago
6 0
Im kinda puzzled on that particular question
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6. Macromolecules represent which level of organization in the body?
hodyreva [135]

Answer:

Chemical

Explanation:

Macromolecules are part of the chemical components of cells. For example, DNA, proteins, and lipids.

Cells of similar types/function form tissues. Different types of tissues interact together to form organs. Organs form a common function.

6 0
3 years ago
A voltaic cell using Cu/Cu²⁺ and Sn/Sn²⁺ half-cells is set up at standard conditions, and each compartment has a volume of 345 m
Nadusha1986 [10]

The mass of copper deposited is 9.589 g .

Given ,

A volatile cell using Cu/Cu2+ and Sn/Sn2+ half cells is set up at standard conditions ,and each compartment has a volume of 345 ml .

current = 0.17 A

time = 48 hrs =48 (60) (60) =172800 sec

we know , I = Q/t

thus , Q ,charge= It = 0.17 (17280) =29376 C

Then ,atomic mass of copper is 63 g

And valency of Cu is 2.

Thus , the equivalent mass of copper is 63/2 = 31.5

We know , 96500 coulombs of electricity produce copper = 31.5 g

29376 C of electricity produce copper =9.589 g

Hence , 9.589 g of Copper is deposited .

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brainly.com/question/18102056

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4 0
1 year ago
When acetic anhydride is dissolved in water, it forms acetic acid according to the balanced chemical reaction shown below. calcu
melisa1 [442]

2(CH3)2O3 + 2H2O   --->   4 CH3COOH  is the balanced equation.


6 0
3 years ago
Which change does an increase in heat energy cause?
Bumek [7]

Answer:

C more collision between molecules

Explanation:

increase in heat causes increase in kinetic energy of the particles

5 0
2 years ago
If 12.5 grams of strontium hydroxide is reacted with 150 mL of 3.5 M carbonic acid, identify the limiting reactant.
vesna_86 [32]

Answer:

Sr(OH)2

Explanation:

We'll begin by calculating the number of mole of carbonic acid in 150mL of 3.5 M carbonic acid solution. This is illustrated below:

Molarity = 3.5M

Volume = 150mL = 150/1000 = 0.15L

Mole of carbonic acid, H2CO3 =..?

Mole = Molarity x Volume

Mole of carbonic acid, H2CO3 = 3.5 x 0.15 = 0.525 mole.

Next, we shall convert 0.525 mole of carbonic acid, H2CO3 to grams.

Mole of H2CO3 = 0.525 mole

Molar mass of H2CO3 = (2x1) + 12 + (16x3) = 62g/mol.

Mass of H2CO3 =..?

Mass = mole x molar mass

Mass of H2CO3 = 0.525 x 62 = 32.55g

Next, we shall write the balanced equation for the reaction. This is given below:

Sr(OH)2 + H2CO3 → SrCO3 + 2H2O

Next, we shall determine the mass of Sr(OH)2 and H2CO3 that reacted from the balanced equation. This is illustrated below:

Molar mass of Sr(OH)2 = 88 + 2(16 + 1) = 88 + 2(17) = 122g/mol

Mass of Sr(OH)2 from the balanced equation = 1 x 122 = 122g

Molar mass of H2CO3 = (2x1) + 12 + (16x3) = 62g/mol.

Mass of H2CO3 from the balanced equation = 1 x 62 = 62g.

From the balanced equation above, 122g of Sr(OH)2 reacted with 62g of H2CO3.

Finally, we shall determine the limiting reactant as follow:

From the balanced equation above, 122g of Sr(OH)2 reacted with 62g of H2CO3.

Therefore, 12.5g of Sr(OH)2 will react with = (12.5 x 62)/122 = 6.35g.

We can see evidently from the calculations made above that it will take 6.35g out 32.55g of H2CO3 to react with 12.5g of Sr(OH)2. Therefore, Sr(OH)2 is the limiting reactant and H2CO3 is the excess reactant

5 0
3 years ago
Read 2 more answers
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