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ArbitrLikvidat [17]
2 years ago
13

Which of the following is an example of a change of state?

Chemistry
1 answer:
lord [1]2 years ago
6 0

Answer:

Option B

Explanation:

  • For Option A the state is not changing but just has different look now.
  • For Option B the state is changing from gas to liquid drops due to cold glass
  • For Option C it hasn't changed state as both corn and flower is solid
  • For Option D paper and ash are both solids

Therefore our answer must be Option B

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Isotopes of carbon differ with the respect to the number of
hodyreva [135]

Answer:

Neutrons.

Explanation:

Isotopes can be defined as the atom of an element that has the same number of protons but different number of neutrons. This ultimately implies that, the isotopes of an element have the same atomic number (number of protons) but different atomic mass (number of nucleons).

The isotope of an element is denoted by X^{A}_{Z}

Where; X is the symbol of the element.

A is the atomic mass or number of nucleons.

Z is the atomic number or number of protons.

<em>Therefore, the number of neutrons = A - Z</em>

<em>Isotopes of carbon differ with respect to the number of neutrons.</em>

<em>Basically, there are three (3) Isotopes of Carbon and these are;</em>

<em>1. Carbon-12: it has an atomic mass of 12 with 6 numbers of proton and neutron respectively. </em>

<em>2. Carbon-13: it has an atomic mass of 13 with 6 numbers of proton and 7 numbers of neutron. </em>

<em>3. Carbon-14: it has an atomic mass of 14 with 6 numbers of proton and 8 numbers of neutron.  </em>

8 0
3 years ago
What happens when acetylene reacts with silver powder?​
horrorfan [7]
It dissolves I think I know I am expert and. Ute
6 0
2 years ago
1. The heat of fusion for the ice-water phase transition is 335 kJ/kg at 0°C and 1 bar. The density of water is 1000 kg/m3 at th
vodomira [7]

Answer:

Expression for the change of melting temperature with pressure..> T₂ = T₁exp(-(P₂-P₁)/(3.61x10⁹ Pa), Freezing Point = 0°C

Explanation:

Derivation from state postulate

Using the state postulate, take the specific entropy,  , for a homogeneous substance to be a function of specific volume  and temperature  .

ds = (partial s/partial v)(t) dv + (partial s/partial T)(v) dT

During a phase change, the temperature is constant, so

ds = (partial s/partial v)(T)  dv

Using the appropriate Maxwell relation gives

ds = (partial P/partial T)(v) dv

s(β) – s(aplαha) = dP/dT (v(β) – v(α))

dP/dT = s(β) – s(α)/v(β) – v(α) = Δs/Δv

Here Δs and Δv are respectively the change in specific entropy and specific volume from the initial phase α to the final phase β.

For a closed system undergoing an internally reversible process, the first law is

du = δq – δw = Tds - Pdv

Using the definition of specific enthalpy, h and the fact that the temperature and pressure are constant, we have

du + Pdv = dh Tds,

ds = dh/T,

Δs = Δh/T = L/T

After substitution of this result into the derivative of the pressure, one finds

dp/dT = L/TΔv

<u>This last equation is the Clapeyron equation.</u>

a)

(dP/dT) = dH/TdV => dP/dlnT = dH/dV

=> dP/dlnT = dH/dV = [H(liquid) - H(solid)]/[V(liquid) - V(solid)]

= [335,000 J/kg]/[1000⁻¹ - 915⁻¹ m³/kg]

= -3.61x10⁹ J/m³ = -3.61x10⁹ Pa

=> P₂ = P₁ - 3.61x10⁹ ln(T₂/T₁) Pa

or

T₂ = T₁exp(-(P₂-P₁)/(3.61x10⁹ Pa)

b) if the pressure in Denver is 84.6 kPa:

T₂(freezing) = 273.15exp[-(84,600-100,000)/(3.61x10⁹)]

≅ 273.15 = 0°C T₁(freezing) essentially no change

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3 years ago
If Earth is in the portion of its orbital path that is further from the Sun, then what can be determined about its rate
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If the earth's orbit is far from the sun, then, its rate will be slower than when it is closer to the Sun. When gravitational field lines get closer together, the magnetic force is strong. We know that the heavier the body is, the stronger its gravitational pull.<span>
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Develop a product by using principles of science to encounter environment related problems
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  • We Are Becoming More Aware Of Our Effect On The Planet
  • We Can Share More Knowledge And Understanding
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3 years ago
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