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nika2105 [10]
2 years ago
13

What is the oxidation number for iodine in Mg(IO3)2 ?

Chemistry
2 answers:
sukhopar [10]2 years ago
8 0

<u>Answer:</u> The oxidation state of iodine atom in the given compound is +5.

<u>Explanation:</u>

Oxidation state is the number that is assigned to an element when it gains or looses electrons. If an element gains electron, it will attain a negative oxidation state and if the element looses electrons, it will attain a positive oxidation state.

For the given chemical compound: Mg(IO_3)_2

We take the oxidation state of iodine atom be 'x'

Oxidation state of magnesium atom = +2

Oxidation state of oxygen atom = -2

Evaluating the oxidation state of iodine atom:

+2+2x+6(-2)=0\\\\x=+5

Hence, the oxidation state of iodine atom in the given compound is +5.

navik [9.2K]2 years ago
7 0
The oxidation number of iodine is 5 in Mg(IO3)2 which can be calculated as 
   Mg(IO3)2
   MgI2O6
As we know that
Mg has +2
O has -2
So,
   (+2) + 2I + 6 (-2)=0
   2 + 2I - 12 =0
   10+ 2I =0
    10 = 2I
     I =5

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Remark
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Rule: if the moles are the same in the equation, then whatever you are given for one, will be the same for the other. So you have 0.854 moles of Ag. You will also have 0.854 moles of AgNO3 

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8 0
3 years ago
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torisob [31]

Answer:

The correct answer is a scientific law.

Explanation:

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3 0
2 years ago
A hot air balloon is filled with 15 moles helium gas and 5 moles nitrogen gas. What is the volume of the balloon at 1.01 atm and
kvasek [131]

<u>Given:</u>

Moles of He = 15

Moles of N2 = 5

Pressure (P) = 1.01 atm

Temperature (T) = 300 K

<u>To determine:</u>

The volume (V) of the balloon

<u>Explanation:</u>

From the ideal gas law:

PV = nRT

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V = volume

n = number of moles of the gas

T = temperature

R = gas constant = 0.0821 L-atm/mol-K

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n(total) = 15 + 5 = 20 moles

P = 1.01 atm and T = 300K

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3 0
3 years ago
Complete combustion of a 0.600-g sample of a compound in a bomb calorimeter releases 24.0 kJ of heat. The bomb calorimeter has a
coldgirl [10]

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<h3>Further explanation</h3>

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Required

The final temperature, t₂

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Q = m.Cs.Δt

Q out (combustion of compound) = Q in (calorimeter)

24,000 = 1300 x 3.41 x (t₂-25.5)

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