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nika2105 [10]
3 years ago
13

What is the oxidation number for iodine in Mg(IO3)2 ?

Chemistry
2 answers:
sukhopar [10]3 years ago
8 0

<u>Answer:</u> The oxidation state of iodine atom in the given compound is +5.

<u>Explanation:</u>

Oxidation state is the number that is assigned to an element when it gains or looses electrons. If an element gains electron, it will attain a negative oxidation state and if the element looses electrons, it will attain a positive oxidation state.

For the given chemical compound: Mg(IO_3)_2

We take the oxidation state of iodine atom be 'x'

Oxidation state of magnesium atom = +2

Oxidation state of oxygen atom = -2

Evaluating the oxidation state of iodine atom:

+2+2x+6(-2)=0\\\\x=+5

Hence, the oxidation state of iodine atom in the given compound is +5.

navik [9.2K]3 years ago
7 0
The oxidation number of iodine is 5 in Mg(IO3)2 which can be calculated as 
   Mg(IO3)2
   MgI2O6
As we know that
Mg has +2
O has -2
So,
   (+2) + 2I + 6 (-2)=0
   2 + 2I - 12 =0
   10+ 2I =0
    10 = 2I
     I =5

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Answer:

  • <u>Cadmium has larger atomic radius than sulfur.</u>

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Down a period, atomic radii decrease from left to right due to the increase in the number of protons and electrons across a period: when a proton is added the pull of the electrons towards the nucleus is larger, so the size of the atom decreases.

Hence, you can compare the elements that belong to a same period and predict that the atom with lower atomic number (number of protons) will haver larger atomic radius. With that:

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