The question requires to balance the equation.
The equation is already balanced, so the answer is:
<span>Ca(s)+Br2(l)⟶CaBr2(s)
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</span><span>Explanation:
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</span><span>1) The phases are identified with a letter to the right of the compound or element:
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</span><span>So, for Ca, the phase is (s) which means solid.
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</span><span>For Br₂ (l) the phase is (l) which means liquid.
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</span><span>For CaBr₂(s) the phase is (s) which means solid.
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</span><span>2) The core work of balancing is make the number of atoms of each element on the reactants equal to the same number of atoms on the products side.
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</span><span>That is the law of conservation of mass applied to chemcial reactions.
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</span><span>3) So, you have to add coefficientes on the right place to make the number of atoms on the left side equal to the number of the same kind of atom on the right side.
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</span><span>In this table you can verify that the equation given is balanced:
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</span><span>atom left side right side
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</span><span>Ca 1 1
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</span><span>Br 2 2
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</span><span>So, you do not need to modify any coefficients.
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Answer:
Different isotopes of the same element have the same number of protons in their atomic nuclei but differing numbers of neutrons. Radioisotopes are radioactive isotopes of an element. They can also be defined as atoms that contain an unstable combination of neutrons and protons, or excess energy in their nucleus.
Answer:
a) excitation radiation
Explanation:
the fluorescence quantum efficiency of the fluorescing molecule:
Molecular structure and its chemical environment influence whether a substance will fluoresce and the intensities of these emissions. The quantum yield or quantum efficiency is used to measure the probability that a molecule will fluoresce or phosphoresce. For fluorescence and phosphorescence is the ratio of the number of molecules that luminescent to the total number of excited molecules. For highly fluoresce molecules, the quantum efficiency approaches to one.Molecules that do not fluoresce have quantum efficiencies that approach to zero.
the molar mass of the compound
Influence of a halogen substitution decreases fluorescence as the molar mass of the halogen increases. This is an example of the “heavy atom effect” which suggest that the probability of intersystem crossing increases as the size of the molecule increases. As the molar mass of the substituted compound increases, the relative intensity of the fluorescence decreases.
The absorptivity of the compound
he molar absorptivity, which measures the probability that a transition will occur
Answer:
It should be A. I've never heard of freezing of sediments