Question

A gas has a pressure of 3.16 atm at STP. I have decided to transfer it to a container that is 3 times larger than the original volume. What is a possible value for Pressure?

Answer 1

Answer:

The new pressure is 1.0533 atm

Explanation:

According  to Boyle's Law : The Pressure of fixed amount of gas is inversely proportional to Volume at constant temperature.

PV = Constant

P1V1 = P2V2

$P_{1}V_{1}=P_{2}V_{2}$.....(1)

P1 = 3.16 atm

Accprding to question ,

V1 = V

V2 = 3 V

Insert the value of V1 , V2 and P1 in the equation(1)

$P_{1}V_{1}=P_{2}V_{2}$

$3.16\times V=P_{2}\times 3V$

V and V cancel each other

$3.16=P_{2}\times 3$

$P_{2}=\frac{3.16}{3}$

$P_{2}=1.05atm$