Answer:
Explanation:
Hello,
In this case, due to the volume displacement caused the by the object's submersion, it's volume is:
In such a way, considering the mathematical definition of density, it turns out:
Rounding to the nearest tenth we finally obtain:
Regards.
CH3 is the empirical formula for the compound.
A sample of a compound is determined to have 1.17g of Carbon and 0.287 g of hydrogen.
The number of atom or moles in the compound is
1.17 g C X 1 mol of C / 12.011 g C = 0.097411 mol of C.
0.287 g H x 1 mol of H / 1 g H = 0.28474 mol H.
This compound contains 0.097411 mol of carbon and 0.28474 mol of Hydrogen.
So we can represent the compound with the formula C0.974H0.284.
Subscripts in formulas can be made into whole numbers by multiplying the smaller subscript by the larger subscript.
we can divide 0.284 by 0.0974.
0.284 / 0.0974 = 3.
So here, Carbon is one and hydrogen is 3.
We can write the above formula as a CH3.
Hence the empirical formula for the sample compound is CH3.
For a detailed study of the empirical formula refer given link brainly.com/question/13058832.
#SPJ1.
The equilibrium constant is a value which represents the equilibrium of a reaction. It is a reaction quotient when the reaction reached equilibrium. If Keq is greater than 1, the mixture contains mostly the products. On the other hand, if Keq is less than 1, the mixture contains the reactants. For this case, the mixture contains mostly products.
Answer:
(D) Neither I nor II
Explanation:
The reagent potassium hydrogen phthalate is found in pure form and it is not partially hydrated .
The pallet form of NaOH ( solid form ) absorbs carbon dioxide gas from the atmosphere but NaOH in solution form does not absorb carbon dioxide .
Hence option D ) is right choice .
Hey there!
Sucrose is C₁₂H₂₂O₁₁.
Find molar mass of sucrose:
C: 12 x 12.01 = 144.12
H: 22 x 1.008 = 22.176
O: 16 x 11 = 176
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342.296 grams
That is the mass of one mole of sucrose.
We have 0.0287.
342.296 x 0.0287 = 9.82
The mass of 0.0287 moles of sucrose is 9.82 grams.
Hope this helps!
