Answer:
0.0102 mole
Explanation:
Use and solve proportions for these with x as the unknown value.
Example
H2SO4
H = 2 atoms
S = 32 atoms
O = 4 atoms
atomic mass :
H = 1 u.m.a
S =32 u.m.a
O= 16 u.m.a
H2SO4 = 1 x 2 + 32 x 1 + 16 x 4 = 98 g/mol
hope this helps!
Answer:
[Cl⁻] = 0.016M
Explanation:
First of all, we determine the reaction:
Pb(NO₃)₂ (aq) + MgCl₂ (aq) → PbCl₂ (s) ↓ + Mg(NO₃)₂(aq)
This is a solubility equilibrium, where you have a precipitate formed, lead(II) chloride. This salt can be dissociated as:
PbCl₂(s) ⇄ Pb²⁺ (aq) + 2Cl⁻ (aq) Kps
Initial x
React s
Eq x - s s 2s
As this is an equilibrium, the Kps works as the constant (Solubility product):
Kps = s . (2s)²
Kps = 4s³ = 1.7ₓ10⁻⁵
4s³ = 1.7ₓ10⁻⁵
s = ∛(1.7ₓ10⁻⁵ . 1/4)
s = 0.016 M
The first answer is B and the second answer is B