<u>Answer-</u>
<em>The probability that in the box there are 1 red and 8 blue markers is</em><em> 0.111 or 11.1%</em>
<u>Solution-</u>
In the box all markers are red or blue. There are total of 9 markers.
So the number of possible combination number of red or blue marker is,
As at the random drawn, there was a Blue marker, so the condition of (9,0) i.e 9 Red marker and 0 Blue marker is not a case.
So the sample space becomes,
Let us assume that E is the event that in the box there are 1 red and 8 blue markers. So
The probability that in the box there are 1 red and 8 blue markers is,
Answer:
-f(3x - 1) + 2 = -18x² + 12x + 1
Step-by-step explanation:
Step 1: Find f(3x - 1)
f(3x - 1) = 2(3x - 1)² - 1
f(3x - 1) = 2(9x² - 6x + 1) - 1
f(3x - 1) = 18x² - 12x + 2 - 1
f(3x - 1) = 18x² - 12x + 1
Step 2: Plug in f(3x - 1)
-(18x² - 12x + 1) + 2
Step 3: Evaluate
-18x² + 12x - 1 + 2
-f(3x - 1) + 2 = -18x² + 12x + 1
If it helps x is all odd numbers