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Helen [10]
4 years ago
15

The circumference of a circle is 28meters. What is it’s radius

Mathematics
2 answers:
uranmaximum [27]4 years ago
8 0

Answer:

Step-by-step explanation:

Given

Circumference = 28 meters

2\pi r  = 28

2 * 3.14 * r = 28

r = 28 /6.28

Therefore r = 4.5 meter

vladimir1956 [14]4 years ago
5 0
<h2><em><u>Answer</u></em><em><u>:</u></em></h2>

<em>Circu</em><em>mference</em><em> </em><em>of</em><em> </em><em>the</em><em> </em><em>circle</em><em> </em><em>=</em><em> </em><em>2</em><em>8</em><em> </em><em>m</em>

<em>Circu</em><em>mference</em><em> </em><em>(</em><em>formula</em><em>)</em><em> </em><em>=</em><em> </em><em>2</em><em>π</em><em>r</em>

<em>Thus</em><em>,</em>

<em>\sf{2\pi r  = 28 \: m }</em>

<em>\sf{ \frac{44r}{7} = 28 \: m }</em>

<em>\sf{r \:  =  \frac{28 \times 7}{44} \: m }</em>

<em>After</em><em> </em><em>solving</em><em> </em><em>,</em>

<em>\sf{r =  \frac{49}{11}  \: m}</em>

<em>After</em><em> </em><em>converting</em><em> </em><em>into</em><em> </em><em>mixed</em><em> </em><em>fraction</em><em>,</em>

<em>\sf{r = 4 \frac{5}{11} \: m \:  }</em>

  • <em>Note</em><em> </em><em>1</em><em> </em><em>:</em><em> </em><em>If</em><em> </em><em>we</em><em> </em><em>want</em><em> </em><em>to</em><em> </em><em>write</em><em> </em><em>our</em><em> </em><em>answer</em><em> </em><em>is</em><em> </em><em>decimal</em><em> </em><em>form</em><em> </em><em>,</em><em> </em><em>we</em><em> </em><em>can</em><em> </em><em>write</em><em> </em><em>it</em><em> </em><em>as</em><em> </em><em>4</em><em>.</em><em>4</em><em>5</em><em> </em><em>m</em><em> </em><em>but</em><em> </em><em>this</em><em> </em><em>answer</em><em> </em><em>will</em><em> </em><em>be</em><em> </em><em>approximate</em><em>.</em>
  • <em>Note</em><em> </em><em>2</em><em> </em><em>:</em><em> </em><em>If</em><em> </em><em>we</em><em> </em><em>want</em><em> </em><em>to</em><em> </em><em>consider </em><em>π</em><em> </em><em>as</em><em> </em><em>3</em><em>.</em><em>1</em><em>4</em><em> </em><em>then</em><em> </em><em>the</em><em> </em><em>answer</em><em> </em><em>will</em><em> </em><em>be</em><em> </em><em>a</em><em> </em><em>bit</em><em> </em><em>different</em><em> </em><em>but</em><em> </em><em>when</em><em> </em><em>we</em><em> </em><em>take</em><em> </em><em>it</em><em> </em><em>as</em><em> </em><em>2</em><em>2</em><em>/</em><em>7</em><em> </em><em>the</em><em> </em><em>answer</em><em> </em><em>is</em><em> </em><em>closer</em><em> </em><em>to</em><em> </em><em>the</em><em> </em><em>exact</em><em> </em><em>one</em><em>.</em>
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Part A

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Mean = 5.7
Standard Deviation = 0.046

-----------------------

The mean is given to us, which was 5.7, so there's no need to do any work there.

To get the standard deviation of the sample distribution, we divide the given standard deviation s = 0.26 by the square root of the sample size n = 32
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================================================

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The 95% confidence interval is roughly (3.73, 7.67)
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-----------------------

At 95% confidence, the critical value is z = 1.96 approximately

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The lower and upper boundaries (L and U respectively) are:
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================================================

Part C

Confidence interval is (5.99, 6.21)
Margin of Error expression is z*s/sqrt(n)
If we generate 100 intervals, then roughly 95 of them will have the mean between 5.99 and 6.21. We are 95% confident that the mean is between those values.

-----------------------

At 95% confidence, the critical value is z = 1.96 approximately

ME = margin of error
ME = z*s/sqrt(n)
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L = lower limit
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L = 5.985713343
L = 5.99

U = upper limit
U = xbar+ME
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