Does a kite and a rhombus have 4 congruent

Kelly plans to put her graduation money into an account and leave it there for 4 years while she goes to college. she recieves $

Firlakuza [10]

Answer:

C) $877.50

Step-by-step explanation:

Time t = 4 years

Principal, p = $750

rate, r = 4.25% = 0.0425

Amount that will be in her account in four years =

Simple interest (prt/100) + principal

750 * 4.25* 4 / 100 + 750

127.5 + 750

= $877.50

7 0

3 years ago

A truck is carrying 513 pounds. There are 27 boxes of chocolate in the truck. About how much does each box weigh?

Volgvan

Answer:

19

Step-by-step explanation:

To solve this, we must divide: 513/27= 19

Have a nice day: Can I please have Brainliest? No biggie if not

3 0

2 years ago

Victoria recently switched to a new electric company. If she uses between 0 and 400 kilowatt-hours (kWh) of electricity per mont

Gekata [30.6K]

Answer:

see the explanation

Step-by-step explanation:

The question is

Identify the domain and the range, using words and inequalities

Let

x -----> the number of kilowatt-hours (kWh) of electricity per month

y ----> the price per month

we know that

Part 1) For the value of x between 0 kWh and 400 kWh

$0\ kWh \leq x < 400\ kWh$

The price is equal to

$y=\$30$

therefore

The domain is the interval ------> [0,400)

The domain is all real numbers greater than or equal to 0 kWh and less than 400 kWh

The range is ($30)

The range is equal to $30

Part 2) For the value of x equal to 400 kWh or more per month

$x\geq 400\ kWh$

The domain is the interval -----> [400, infinite)

The domain is all real numbers greater than or equal to 400 kWh

The price is

$y=0.097x$

Find the range

For x=400 kWh

$y=0.097(400)=\$38.8$

so

$y\geq \$38.8$

The range is the interval -----> [38.8, infinite)

7 0

3 years ago

An automobile manufacturer has given its van a 31.3 miles/gallon (MPG) rating. An independent testing firm has been contracted t

Fynjy0 [20]

Answer:

$z=\frac{31.1-31.3}{\frac{1.3}{\sqrt{140}}}=-1.82$

The p value for this case would be given by:

$p_v =2*P(z$

For this case since the p value is higher than the significance level we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true mean is not significantly different from 31.3 MPG

Step-by-step explanation:

Information given

$\bar X=31.1$ represent the sample mean

$\sigma=1.3$ represent the population standard deviation

$n=140$ sample size

$\mu_o =31.3$ represent the value that we want to test

$\alpha=0.02$ represent the significance level for the hypothesis test.

z would represent the statistic

$p_v$ represent the p value

Hypothesis to test

We want to test if the true mean is equal to 31.3 MPG, the system of hypothesis would be:

Null hypothesis: $\mu =31.3$

Alternative hypothesis: $\mu \neq 31.3$

Since we know the population deviation, the statistic is given by

$z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}$ (1)

Replacing we got:

$z=\frac{31.1-31.3}{\frac{1.3}{\sqrt{140}}}=-1.82$

The p value for this case would be given by:

$p_v =2*P(z$

For this case since the p value is higher than the significance level we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true mean is not significantly different from 31.3 MPG

4 0

3 years ago

A class counts the number of vehicles that pass by its school from 1 :00 to 2:00 pm there are 3 times as many cars as trucks

Pepsi [2]

Ok So From What You Said I Calculated This:

1:00-2:00

cars=c, trucks=t
answer=a

c x 3 = a
a÷3=t

4 0

2 years ago