The x coordinate of the vertex will be the average of the two zeros, here -3 and 5, so x=(-3+5)/2 = 1, f(1)=(1+3)(1-5) = -16.
Answer: (1, -16)
Let's do it some other ways. How about completing the square to turn f in to vertex form?
f(x) = (x+3)(x-5) = x² - 2x - 15 = (x² - 2x + 1) - 1 - 15 = (x-1)² - 16
and now we can read off (1, -16) as the vertex.
The other method is the vertex is x= - b/2a = - (-2)/2(1) = 1.
Three methods, same answer. Good.
Answer:
x=1
Step-by-step explanation:
By factoring, you'll compress the equation to (x-1)^2=0
Next take out the square: x-1=0
Now subtract one to the other side to get x! x=1
Hope this helps! :)
if its diameter is 34, then its radius is half that or 17.
![\textit{surface area of a sphere}\\\\ SA=4\pi r^2 ~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r=17 \end{cases}\implies \begin{array}{llll} SA=4\pi (17)^2\implies SA=1156\pi \\\\\\ SA\approx 3631.68~m^2 \end{array}](https://tex.z-dn.net/?f=%5Ctextit%7Bsurface%20area%20of%20a%20sphere%7D%5C%5C%5C%5C%20SA%3D4%5Cpi%20r%5E2%20~~%20%5Cbegin%7Bcases%7D%20r%3Dradius%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20r%3D17%20%5Cend%7Bcases%7D%5Cimplies%20%5Cbegin%7Barray%7D%7Bllll%7D%20SA%3D4%5Cpi%20%2817%29%5E2%5Cimplies%20SA%3D1156%5Cpi%20%5C%5C%5C%5C%5C%5C%20SA%5Capprox%203631.68~m%5E2%20%5Cend%7Barray%7D)
in the denominator is missing in the second expression. It should be
