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asambeis [7]
3 years ago
10

3y^4+9y^3-120y^2=0 Need Answer ASAP

Mathematics
2 answers:
Shkiper50 [21]3 years ago
7 0

Answer:

y  =  0 ,  5 ,  − 8

(* ̄3 ̄)╭

andrey2020 [161]3 years ago
5 0

3y^4+9y^3-120y^2=0\\y=0,5,8

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Solve <br> y= -2x + 9<br><br> y= 4x -3
wlad13 [49]

y = -2x + 9

y = 4x - 3

y is isolated in both equations, thus you may set the expressions (-2x + 9) and (4x - 3) equal to each other and solve for x.

-2x + 9 = 4x - 3

Subtract 9 from both sides.

-2x + 9 - 9 = 4x - 3 - 9

-2x = 4x - 12

Subtract 4x from both sides.

-2x - 4x = 4x - 12 - 4x

-6x = -12

Divide both sides by -6.

-6x/-6 = -12/-6

x = 2

Substitute 2 for x into one of the original equations to find y.

y = 4x - 3 (given)

y = 4(2) - 3 (substitute)

y = 8 - 3 (multiply)

y = 5 (subtract)

Plug x- and y-values into original equations to check work.

5 = -2(2) + 9

5 = - 4 + 9

5 = 5


5 = 4(2) - 3

5 = 8 - 3

5 = 5

Answer:

x = 2 and y = 5; (2, 5).

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klasskru [66]

Answer:

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one pump, let's call it A, fills the reservoir by 1/60 every hour. Now, B fills it by 1/80 every hour. C empties it by 1/90 every hour. All three are on, so now we combine them into one function: t(1/60 + 1/80 - 1/90) = 1, where t = the time it takes to fill it, and 1 is just our "reservoir finally filled" marker.

isolate t onto one side and we see t = 720/13 exactly, or approximately 55.38 hours. let me know if this is the wrong answer but I'm pretty sure it is correct!

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3 years ago
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