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d1i1m1o1n [39]
3 years ago
10

What is the equation, in point slope form, of the line

Mathematics
1 answer:
melamori03 [73]3 years ago
5 0

Answer:

y=3/2x+11/2

Step-by-step explanation:

Hello! Sorry  I just saw this

Anyways, let's continue

first, we need to find the equation of the line with the one that is (-2,-4) and (2,2)

first, we need to find the slope

the equation for slope is y2-y1/x2-x1

so let's label the points

x1=-2

y1=-4

x2=2

y2=2

now plug it in

2-(-4)/2-(-2)=6/4=3/2

now, let's turn it into a line

the point-slope form is y-y1=m(x-x1) (m=slope)

now, plug it in

y-(-4)=3/2(x-(-2))

simplify to

y+4=3/2(x+2)

turn into y=mx+b format

y+4=3/2x+3

subtract 4 on both sides

y=3/2x-1

Now for the line that is parallel.

Parallel lines have the same slopes, so you automatically know that the new line will be y=3/2x+b

To make sure (-3,1) is a solution to the point, put 1 as y and -3 as x

1=3/2(-3)+b

1=-9/2+b

add 9/2 on both sides

b=11/2 or 5.5

now, put it into the equation

y=3/2x+11/2

Hope this helps!

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3 years ago
8t – 13t + 10 (t – 2) = 34
MrRa [10]

Answer:

t=10.9

Step-by-step explanation:

8t-13t+10(t-2)=34

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3 0
3 years ago
A normally distributed population has mean 57,800 and standard deviation 750. Find the probability that a single randomly select
Stels [109]

Answer:

(a) Probability that a single randomly selected element X of the population is between 57,000 and 58,000 = 0.46411

(b) Probability that the mean of a sample of size 100 drawn from this population is between 57,000 and 58,000 = 0.99621

Step-by-step explanation:

We are given that a normally distributed population has mean 57,800 and standard deviation 75, i.e.; \mu = 57,800  and  \sigma = 750.

Let X = randomly selected element of the population

The z probability is given by;

           Z = \frac{X-\mu}{\sigma} ~ N(0,1)  

(a) So, P(57,000 <= X <= 58,000) = P(X <= 58,000) - P(X < 57,000)

P(X <= 58,000) = P( \frac{X-\mu}{\sigma} <= \frac{58000-57800}{750} ) = P(Z <= 0.27) = 0.60642

P(X < 57000) = P( \frac{X-\mu}{\sigma} < \frac{57000-57800}{750} ) = P(Z < -1.07) = 1 - P(Z <= 1.07)

                                                          = 1 - 0.85769 = 0.14231

Therefore, P(31 < X < 40) = 0.60642 - 0.14231 = 0.46411 .

(b) Now, we are given sample of size, n = 100

So, Mean of X, X bar = 57,800 same as before

But standard deviation of X, s = \frac{\sigma}{\sqrt{n} } = \frac{750}{\sqrt{100} } = 75

The z probability is given by;

           Z = \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)  

Now, probability that the mean of a sample of size 100 drawn from this population is between 57,000 and 58,000 = P(57,000 < X bar < 58,000)

P(57,000 <= X bar <= 58,000) = P(X bar <= 58,000) - P(X bar < 57,000)

P(X bar <= 58,000) = P( \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } <= \frac{58000-57800}{\frac{750}{\sqrt{100} } } ) = P(Z <= 2.67) = 0.99621

P(X < 57000) = P( \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } < \frac{57000-57800}{\frac{750}{\sqrt{100} } } ) = P(Z < -10.67) = P(Z > 10.67)

This probability is that much small that it is very close to 0

Therefore, P(57,000 < X bar < 58,000) = 0.99621 - 0 = 0.99621 .

7 0
3 years ago
Can anyone solve these 3 equations?
Nesterboy [21]

Answer:

1. x = 1, -2

2.  no solution

3.  x = 6 -4

hope this helps!

Step-by-step explanation:


3 0
3 years ago
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