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d1i1m1o1n [39]
3 years ago
10

What is the equation, in point slope form, of the line

Mathematics
1 answer:
melamori03 [73]3 years ago
5 0

Answer:

y=3/2x+11/2

Step-by-step explanation:

Hello! Sorry  I just saw this

Anyways, let's continue

first, we need to find the equation of the line with the one that is (-2,-4) and (2,2)

first, we need to find the slope

the equation for slope is y2-y1/x2-x1

so let's label the points

x1=-2

y1=-4

x2=2

y2=2

now plug it in

2-(-4)/2-(-2)=6/4=3/2

now, let's turn it into a line

the point-slope form is y-y1=m(x-x1) (m=slope)

now, plug it in

y-(-4)=3/2(x-(-2))

simplify to

y+4=3/2(x+2)

turn into y=mx+b format

y+4=3/2x+3

subtract 4 on both sides

y=3/2x-1

Now for the line that is parallel.

Parallel lines have the same slopes, so you automatically know that the new line will be y=3/2x+b

To make sure (-3,1) is a solution to the point, put 1 as y and -3 as x

1=3/2(-3)+b

1=-9/2+b

add 9/2 on both sides

b=11/2 or 5.5

now, put it into the equation

y=3/2x+11/2

Hope this helps!

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Which matrix represents the system of equations shown below? 3x-5y=12 4x-2y=15
tatuchka [14]

Answer:

\left[\begin{array}{ccc}3&-5  &|12\\4&-2  &|15\\\end{array}\right]

Step-by-step explanation:

When making a matrix of two equations with the variables x and y, the result will be a matrix with three columns:

  • a column for the values of x in each equation
  • a column for the values of y in each equation
  • a column for the independent values of each equation

since our system of equations is:

3x-5y=12\\ 4x-2y=15

we can see that the value for x in the first equation is 3 and in the second equation is 4, thus the first column will have the numbers 3 and 4:

\left[\begin{array}{ccc}3&&\\4&&\\\end{array}\right]

Now for the values of y we hvae -5 in the first equation and -2 in the second equation, we update the matrix with another column with the values of -5 and -2:

\left[\begin{array}{ccc}3&-5&\\4&-2&\\\end{array}\right]

Finally, the last column is the independent values of each equation (or the results) in the first equation that number is 12 and in the second equation is 15, thus the matrix is:

\left[\begin{array}{ccc}3&-5&12\\4&-2&15\\\end{array}\right]

usually there is a line separating the columns for the values of x and y, and the independent values:

\left[\begin{array}{ccc}3&-5  &|12\\4&-2  &|15\\\end{array}\right]

this is the matrix of the system of equations

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Step-by-step explanation:

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Step-by-step explanation:

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