What is the problem I don’t see an attachment
Answer:
10 people
Step-by-step explanation:
First, I subtracted $16.75 from $390. I got an answer of $373.25. Next, I divided $373.25 by 34 people. The answer then rounded out to 10 People. So in conclusion 10 people can go to the amusment park.
Answer:
Option a is correct.
Step-by-step explanation:
Since both fiber and sugar are types of carbohydrates and it is given that a portion of food has 24 gm of total carbohydrate and within which 2 gm of fiber and 12 gm of sugar.
Therefore, this food contains 2 g of fiber, 12 g of sugars, and 10 g of other unnamed carbohydrates, for a total of 24 g.
Hence, option (a) is correct. (Answer)
Use the chain rule:
<em>y</em> = tan(<em>x</em> ² - 5<em>x</em> + 6)
<em>y'</em> = sec²(<em>x</em> ² - 5<em>x</em> + 6) × (<em>x</em> ² - 5<em>x</em> + 6)'
<em>y'</em> = (2<em>x</em> - 5) sec²(<em>x</em> ² - 5<em>x</em> + 6)
Perhaps more explicitly: let <em>u(x)</em> = <em>x</em> ² - 5<em>x</em> + 6, so that
<em>y(x)</em> = tan(<em>x</em> ² - 5<em>x</em> + 6) → <em>y(u(x))</em> = tan(<em>u(x)</em> )
By the chain rule,
<em>y'(x)</em> = <em>y'(u(x))</em> × <em>u'(x)</em>
and we have
<em>y(u)</em> = tan(<em>u</em>) → <em>y'(u)</em> = sec²(<em>u</em>)
<em>u(x)</em> = <em>x</em> ² - 5<em>x</em> + 6 → <em>u'(x)</em> = 2<em>x</em> - 5
Then
<em>y'(x)</em> = (2<em>x</em> - 5) sec²(<em>u</em>)
or
<em>y'(x)</em> = (2<em>x</em> - 5) sec²(<em>x</em> ² - 5<em>x</em> + 6)
as we found earlier.
