is the ΔS°rxn for the formation of Cu₂O(s) from its elements.
WHAT IS ΔS°rxn FOR THE REACTION ?
The direction of spontaneous change is the direction in which total entropy increases. Total entropy change, also called the entropy change of the universe, is the sum of the entropy change of a system and of its surroundings
Standard entropy change of below reaction (ΔS°
)
∴ ΔH° = - 168.6 KJ/mol
Now, 
![= S^o_{Cu_2 O(s)} - [2 * S^o_{Cu(s)} + \frac{1}{2}(S^o_{O_2(g)}]](https://tex.z-dn.net/?f=%3D%20S%5Eo_%7BCu_2%20O%28s%29%7D%20-%20%5B2%20%2A%20S%5Eo_%7BCu%28s%29%7D%20%2B%20%5Cfrac%7B1%7D%7B2%7D%28S%5Eo_%7BO_2%28g%29%7D%5D)
![= (93.1 J/molK)- [2 * 133.1 + \frac{1}{2}(205.0)]J/molK](https://tex.z-dn.net/?f=%3D%20%2893.1%20J%2FmolK%29-%20%5B2%20%2A%20133.1%20%2B%20%5Cfrac%7B1%7D%7B2%7D%28205.0%29%5DJ%2FmolK)
Thus, -75.6 J/mol K is the ΔS°rxn for the formation.
Learn more about ΔS°rxn FOR THE REACTION are:
brainly.com/question/13013699
#SPJ4
False, other planets have things we have not discovered yet, but for one thing for sure there are storms and hurricanes on other planets as well.
Answer:
The correct answer is - alpha particle and positron.
Explanation:
In this question, it is given that, 38^88Sr decays to 34^84Kr, which means there is an atomic number decrease by 4, 38 to 34, and atomic mass decreases by 4 as well 88 to 84.
A decrease in the atomic mass is possible only when there is an emission of the alpha particle as an alpha particle is made of 2 protons and 2 neutrons. If an atom emits an alpha particle, there is a change in atomic number as it decreases by two, and its mass number decreases by four.
So after the emission of an alpha particle, the new atom would be
38^88Sr=> 36^84X => 34^84Kr
so there is also two positron emission that leads to decrease in atomic number by one with each emission:
38^88Sr=> 2^4He+ 36^84X => 36^84X + 2(1^0β+) => 34^84Kr
Positron decay is the conversion of a proton into a neutron with the emission of a positron that causes the atomic number is decreased by one, which causes a change in the elemental identity of the daughter isotope.
Answer:
Explanation:
Hello,
In this case, we can first compute the volume of the sample in mL from the ounces:
Thus, with the volume of the sample, we can compute the amount of sugar given the 10 g of sugar per 100 mL of soft drink as shown below:
Best regards.
