Answer:
a) 7.0 moles of NH3
b) 61.2 g of NH3
c) 4.15 g of H2
d) 8.9 ×10^19 molecules
Explanation:
Equation of the reaction;
N2(g) + 3H2(g) ⇄NH3(g)
a)
If 3 moles of H2 yields 1 mole of NH3
21 moles of H2 will yield 21 × 1 /3 = 7.0 moles of NH3
b)
1 mole of N2 yields 17 g of NH3
3.6 moles of N2 yields 3.6 moles × 17 g of NH3 = 61.2 g of NH3
c)
If 6g of H2 produces 17 g of NH3
xg of H2 will produce 11.76 g of NH3
x= 6 × 11.76/17
x= 4.15 g of H2
d)
If 6g of hydrogen yields 6.02 × 10^23 molecules of NH3
8.86 × 10^-4g of H2 yields 8.86 × 10^-4g × 6.02 × 10^23 /6 = 8.9 ×10^19 molecules
Answer:
49.4 g Solution
Explanation:
There is some info missing. I think this is the original question.
<em>A chemistry student needs 20.0g of acetic acid for an experiment. He has 400.g available of a 40.5 % w/w solution of acetic acid in acetone. </em>
<em>
Calculate the mass of solution the student should use. If there's not enough solution, press the "No solution" button. Round your answer to 3 significant digits.</em>
<em />
We have 400 g of solution and there are 40.5 g of solute (acetic acid) per 100 grams of solution. We can use this info to find the mass of acetic acid in the solution.
Since we only need 20.0 g of acetic acid, there is enough of it in the solution. The mass of solution that contains 20.0 g of solute is:
The reagents which are used to carry out the chlorination of benzene are cl2/fecl3 and cl2/nacl
Chlorination is the process of disinfecting drinking water by introducing chlorine to eradicate viruses, germs, and parasites. To get drinking water with safe levels of chlorine, various techniques can be utilized. Chlorination is the technique of disinfecting and eradicating bacteria from drinking water by adding chlorine to it.
To get drinking water with safe levels of chlorine, various techniques can be utilized. Chlorine can be found as solid calcium hypochlorite (Ca(OCl)2), sodium hypochlorite solution (NaOCl), or compressed elemental gas. Chlorine is added to water as part of the chlorination process, however the chlorinating substance need not be pure chlorine.
To learn more about chlorination please visit -
brainly.com/question/14962130
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Answer:
61.39%
Explanation:
The percent yield of a substance can be calculated using the formula:
Percent yield = actual yield/theoretical yield × 100%
Based on the information provided on the reaction in this question, the theoretical yield is given as 99.2g while the actual yield is given as 60.9g.
Hence, the percent yield is calculated thus:
% yield = 60.9/99.2 × 100
% yield = 0.6139 × 100
% yield = 61.39%
The percent yield is 61.39%
