What is the combining ratio of potassium with bromine?

Describe the law of conservation of energy. Provide at least one example that illustrates this law. (4 points)

SCORPION-xisa [38]

The law of conservation of energy states that energy is neither created nor destroyed; the amount remains constant. For example, a form of energy-thermal energy, or heat, occurs by convection or conduction

6 0

4 years ago

Q2.

zzz [600]

Answer:

800W

Explanation:

Given the following data;

Voltage = 230 V

Model = VSO Ha

Power = 800 W

Power is calculated by the multiplication of voltage and current flowing through an electric circuit.

Mathematically, power is given by the formula;

Power = current * voltage

The S.I unit for power is Watts and it is a measure of the energy consumption of an electronic device.

3 0

3 years ago

The velocity of a an object in linear motion changes from +25 meters per second to +15 meters per second in 2.0 seconds.

kodGreya [7K]

Answer:

$-5.0 m/s^2$

Explanation:

Missing question:

What is the object's acceleration?

Solution:

The acceleration of an object is given by

$a=\frac{v-u}{t}$

where

v is the final velocity

u is the initial velocity

t is the time taken for the change in velocity

For the object in this problem,

u = +25 m/s

v = +15 m/s

t = 2.0 s

Substituting,

$a=\frac{15-25}{2}=-5.0 m/s^2$

And the acceleration is negative because its direction is opposite to that of the velocity.

5 0

3 years ago

I NEED PHYSICS HELP? THE QUESTION IS IN THE PIC

Marina CMI [18]

Speed of the block at the bottom of the incline: 5.42 m/s

The first part of the problem can be solved by using the law of conservation of energy. Since the ramp is frictionless, the initial gravitational potential energy of the block at the top of the ramp is converted into kinetic energy at the bottom:

$mgh = \frac{1}{2}mv^2$ (1)

where

m is the mass of the block

g = 9.8 m/s^2 is the acceleration of gravity

h is the initial height of the block

v is the speed of the block at the bottom

The initial height of the block is equal to the height of the ramp, so

$h=L sin \theta$ (2)

where

L = 3.00 m is the length of the ramp

$\theta=30^{\circ}$ is the angle of the ramp

Substituting (2) into (1) and re-arranging the equation, we find the speed

$2gL sin \theta = v^2$

$v=\sqrt{2gL sin \theta}=\sqrt{2(9.8)(3.00)sin 30^{\circ}}=5.42 m/s$

Coefficient of kinetic friction between the floor and the block: 0.3

In the second part of the motion, the block is slowed down by friction along the flat surface. According to the work-energy theorem, the work done by friction is equal to the change in kinetic energy of the block:

$W=\Delta K=K_f -K_i$

where

W is the work done by friction

Kf is the final kinetic energy of the block, which is zero since the block comes to rest

$K_i = \frac{1}{2}mv^2$ is the initial kinetic energy of the block, where

m = 10.0 kg is the mass of the block

v = 5.42 m/s is its initial speed

Substituting into the equation, we find

$W=-\frac{1}{2}mv^2=-\frac{1}{2}(10.0)(5.42)^2=-146.9 J$

and the work is negative, since the direction of the force of friction is opposite to the direction of motion of the block.

Now we can rewrite the work as the product between the force of friction and the displacement of the block:

$W=-F_f d = - \mu mg d$

where

$\mu$ is the coefficient of friction

d = 5.00 m is the displacement of the block

Solving for $\mu$ ,

$\mu = - \frac{W}{mgd}=-\frac{-146.9}{(10.0)(9.8)(5.00)}=0.3$

4 0

3 years ago

One advantage of light microscopy over transmission electron microscopy is that One advantage of light microscopy over transmiss

il63 [147K]

Answer:

d. light microscopy allows one to view dynamic processes in living cells.

Explanation:

One advantage of light microscopy over transmission electron microscopy is that light microscopy allows one to view dynamic processes in living cells.

Electron microscope differ from the light microscope because electron micoscope produce the image of the specimen using electron beam and not light. Electron microscopy samples must be kept in vacuum, this means live cells can not be imaged.

4 0

4 years ago