Question

Alex and Josh rode bikes. Alex rode 15 miles in 55 minutes. Josh rode 77 minutes at a faster rate per mile than Alex. Find Alex's unit rate in minutes per mile. What is Josh's rate per mile?

Answer 1

Answer:

a) $x = \frac{11}{3}\,\frac{min}{mi}$, b) $y = \frac{77}{15}\,\frac{min}{mi}$

Step-by-step explanation:

a) The indicator is equal to the ratio of total time to travelled distance:

Alex

$x = \frac{55\,min}{15\,mi}$

$x = \frac{11}{3}\,\frac{min}{mi}$

b) In the case of Josh, the ratio must be greater than x. Then:

$y = \frac{77\,min}{15\,mi}$

$y = \frac{77}{15}\,\frac{min}{mi}$