Initial velocity of the plane is Vo = 0.
acceleration a = 1.3 m/s2
total distance = 2.5 km = 2500m
time taken to reach 2.5 km with 1.3m/s^2 acceleration = t
S = Vo t + 0.5 a t^2
2500 = 0 + (0.5*1.3* t^2)
t^2 = 3846.15
t = 62 s
the maximum velocity plan can reach within 62 s is Vt
Vt = Vo + a t
Vt = 0 + (1.3*62)
Vt = 80.6 m/s
Since 80.6 m/s is greater than 75 m/s, plane can use this runway to takeoff with required speed.
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Answer: p - 0.2p
Step-by-step explanation:
Given the following :
Original Price of tennis racket = p
Mark down or discount on original price = 20% of original price = (20/100) × p = 0.2p
Amount after discount = Amount paid by Natasha
Amount after discount = Original price - Discount
Amount after discount = p - 0.2p
Amount paid by Natasha = p - 0.2p
Answer:
-24 is your answer<3.....
Answer: The gradient of the line passing through is 3, thus the equation of the line becomes y=3x-4.
Step-by-step explanation: The parallel lines gradients that have similar gradients, so now we have the gradient of 3 because its similar to the other gradient. To get the equation of the line we use this equation: y=mx+c, we have to substitute the x and y to get the constant c.
5=3(3)+c
c= -4
y=3x+c
