Answer:
AE = 21.471cm long
(Rounded to 3 sig figs would be 21.5cm)
Step-by-step explanation:
Use the pythagorean theorem to find the length of AH
10^2 + AH^2 = 25^2
AH^2= (625 - 100)
AH = Square root of (525)
AH = 22.913
Plug in this value for AH to solve for AE using the pythagorean theorem
HE^2 + AE^2 = AH^2
8^2 + AE^2 = 22.913^2
AE^2 = 525 - 64
AE = Square root of (461)
AE = 21.4709
Hope this helps!
Answer:
A and D. SSS theorem
B. ASA or AAS theorems
C. SAS theorem
E. AAS theorem
Step-by-step explanation:
SSS theorem states that if three sides of one triangle are congruent to three sides of another triangle, then these two triangles are congruent.
SAS theorem states that if two sides and the included angle of one triangle are congruent to two sides and the included angle of another triangle, then these two triangles are congruent.
AAS theorem states that if two angles and the non-included side one triangle are congruent to two angles and the non-included side of another triangle, then these two triangles are congruent.
ASA theorem states that if two angles and the included side of one triangle are congruent to the corresponding parts of another triangle, then the triangles are congruent.
Thus:
A. If each pair of corresponding sides is congruent, then two triangles are congruent by SSS theorem.
B. If two pairs of corresponding angles are congruent and a pair of corresponding sides are congruent, then two triangles are congruent by ASA or AAS theorems.
C. If two pairs of corresponding sides and the angles included between them are congruent, then two triangles are congruent by SAS theorem.
D. If three sides of one triangle are congruent to three sides of a second triangle, then two triangles are congruent by SSS theorem.
E. If two angles and a non-included sides of each triangle are congruent, then two triangles are congruent by AAS theorem.
When reflected across Y = 3.
L = (-3,5)
U = (-3,1)
X = (0,1)
Answer:
0.0008
Step-by-step explanation:
9514 1404 393
Answer:
2 < x < 15
Step-by-step explanation:
The triangle inequality requires all of ...
(x +11) +(2x +10) > (5x -9) ⇒ 30 > 2x
(2x +10) +(5x -9) > (x +11) ⇒ 6x > 10
(5x -9) +(x +11) > (2x +10) ⇒ 4x > 8
The solutions to these are ...
x < 15
x > 5/3
x > 2
So, the final requirement that has x satisfying all of these is ...
2 < x < 15
