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sladkih [1.3K]
3 years ago
7

Assume that light of wavelength 6000A is coming from a star. What is the limit of resolution of a telescope whose objective has

a diameter of 100 inch?
Engineering
1 answer:
Paul [167]3 years ago
4 0

Answer:

θ=0.0288 radian

Explanation:

resolution limit is the minimum angular separation of  two sources that can be viewed  distinctly    by telescope

\theta =\frac{1.22\times \lambda}{D}

\lambda=6000\times 10^{-8} cm=6 \times 10^{-5} cm

d=100 inch=100\times 2.54=254cm

\theta = \frac{1.22 \times 6 \times 10^{-5}}{254}

θ=0.0288 radian

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A "scale" is constructed with a 4-ft-long cord and the 10-lb block D. The cord is fixed to a pin at A and passes over two small
Anarel [89]

Answer:

attached below

Explanation:

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3 years ago
Question 5 of 10
Angelina_Jolie [31]

The cubic inch space that is required inside a box for 4 #6 XHHN current carrying conductors will be D. 8 cubic inches.

<h3>What is a conductor?</h3>

It should be noted that a conductor simply means a substance or material that simply allows electricity to pass through it.

From the information given, the cubic inch space that is required inside a box for 4 #6 XHHN current carrying conductors is yo be computed.

This will be:

= (4 × 6)/3

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In conclusion, the cubic inch space that is required inside a box for 4 #6 XHHN current carrying conductors will be 8 cubic inches.

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2 years ago
Write a loop that sets each array element to the sum of itself and the next element, except for the last element which stays the
kotykmax [81]

Hi, you haven't provided the programing language in which you need the code, I'll explain how to do it using Python, and you can follow the same logic to make a program in the programing language that you need.

Answer:

#Python

array = [5,2,3,4,5,0,7,1,9,8,2,7]

for i in range(len(array)-1):

   array[i] = array[i]+array[i+1]

print(array)

Explanation:

First, we create an array, then a for loop that iterates from the beginning of the array to the penultimate value, this avoids changes in the last value of the array, we modify the array elements, except the last one, by adding the current element and the next element, finally, we print the result.

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If the reading of mercury manometer was 728 mmHg, what is the reading for another liquid such as water in mH20 units?​
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Answer:

mH275 units

Explanation:

  • that was true
4 0
3 years ago
The absolute pressure in water at a depth of 9 m is read to be 185 kPa. Determine: a. The local atmospheric pressure b. The abso
ser-zykov [4K]

Answer:

a)Patm=135.95Kpa

b)Pabs=175.91Kpa

Explanation:

the absolute pressure is the sum of the water pressure plus the atmospheric pressure, which means that for point a we have the following equation

Pabs=Pw+Patm(1)

Where

Pabs=absolute pressure

Pw=Water pressure

Patm= atmospheric pressure

Water pressure is calculated with the following equation

Pw=γ.h(2)

where

γ=especific weight of water=9.81KN/M^3

H=depht

A)

Solving using ecuations 1 y 2

Patm=Pabs-Pw

Patm=185-9.81*5=135.95Kpa

B)

Solving using ecuations 1 y 2, and atmospheric pressure

Pabs=0.8x5x9.81+135.95=175.91Kpa

8 0
4 years ago
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