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Neko [114]
3 years ago
13

A chemistry student accidentally drops a large mercury thermometer and it breaks. The thermometer contained 2 grams of mercury (

Hg), a potent neurotoxin. The Hg leaks out and pools together into a droplet on the floor of the laboratory. The Occupational Safety and Health Administration (OSHA) sets the permissible exposure limit (PEL) for mercury vapor in air at 12 parts per billion, by volume. At no time should anyone be exposed to mercury vapor above this threshold. The molar mass of Hg is 201 g/mol. The temperature and pressure in the lab are 14.7 psia and 70°F, respectively.
Engineering
1 answer:
loris [4]3 years ago
4 0

Answer:

23.1 35f

Explanation:

not dumb

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asambeis [7]

The roads have pre-described lanes that should follow a particular speed and rules. When a driver drives slowly than he makes the other drivers impatient.

<h3>What are traffic rules?</h3>

Traffic rules are the regulations that are defined to regulate the vehicles and other conveyances that walk on the road. They are different in various places and have separate punishments for not following them.

The left lane of the road is generally for the drivers who want to pass by the vehicle ahead by following the mph rule. If the driver drives slowly then they make the other people impatient and result in honking.

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2 years ago
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Why does my man bun not have its own erodynamics
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umm okay for starters I have no clue lol.

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3 years ago
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3 years ago
A storage tank, used in a fermentation process, is to be rotationally molded from polyethylene plastic. This tank will have a co
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Answer:

The volume up to cylindrical portion is approx  32355 liters.

Explanation:

The tank is shown in the attached figure below

The volume of the whole tank is is sum of the following volumes

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V_{hem}=\frac{2}{3}\pi r^3

2) Cylindrical Middle section

Volume of cylindrical middle portion of radius 'r' and height 'h'

V_{cyl}=\pi r^2\cdot h

3) Conical bottom

Volume of conical bottom of radius'r' and angle \theta is

V_{cone}=\frac{1}{3}\pi r^3\times \frac{1}{tan(\frac{\theta }{2})}

Applying the given values we obtain the volume of the container up to cylinder is

V=\pi 1.5^2\times 4.0+\frac{1}{3}\times \frac{\pi 1.5^{3}}{tan30}=32.355m^{3}

Hence the capacity in liters is V=32.355\times 1000=32355Liters

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