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stealth61 [152]
3 years ago
9

Nitrate salts (NO3-), when heated, can produce nitrites (NO2-) plus oxygen (O2). A sample of potassium nitrate is heated, and th

e O2 gas produced is collected in a 720 mL flask. The pressure of the gas in the flask is 2.9 atm, and the temperature is recorded to be 319 K. The value of R= 0.0821 atm L/(mol K)
How many moles of O2 gas were produced?

After a few hours, the 720 mL flask cools to a temperature of 293K.

Pnew = atm

What is the new pressure due to the O2 gas?
Engineering
1 answer:
Mice21 [21]3 years ago
5 0

Answer:

0.07973 moles of O2 gas were produced

2.66 atm

Explanation:

Using the ideal gas equation

PV =nRT

P =pressure = 2.9 atm

V= volume = 720 mL =  720mL/1000= 0.72 L

n = number of moles = ?

R = the gas constant = 0.0821 atm L/(mol K)

T = temperature in Kelvin = 319 K

make n subject of the formula

n =PV/RT

n = 2.9 atm x 0.72 L / 0.0821 atm L/(mol K) x 319K = 0.07973 moles of O2 gas were produced

Pnew = atm?

P = nRT/V

 = 0.07973 x 0.0821 atm L/(mol K) x 293K/0.72 L = 2.66 atm

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A triangular roadside channel is poorly lined with riprap. The channel has side slopes of 2:1 (H:V) and longitudinal slope of 2.
Oliga [24]

Answer:

Q = 14.578 m³/s

Explanation:

Given

We use the Manning Equation as follows

Q = (1/n)*A*(∛R²)*(√S)

where

  • Q = volumetric water flow rate passing through the stretch of channel (m³/s for S.I.)
  • A = cross-sectional area of flow perpendicular to the flow direction, (m² for S.I.)
  • S = bottom slope of channel, m/m (dimensionless) = 2.5% = 0.025
  • n = Manning roughness coefficient (empirical constant), dimensionless = 0.023
  • R = hydraulic radius = A/P (m for S.I.) where :
  • A = cross-sectional area of flow as defined above,
  • P = wetted perimeter of cross-sectional flow area (m for S.I.)

we get A as follows

A = (B*h)/2

where

B = 5 m (the top width of the flowing channel)

h = (B/2)*(m) = (5 m/2)*(1/2) = 1.25 m   (the deep)

A = (5 m*1.25 m/2) = 3.125 m²

then we find P

P = 2*√((B/2)²+h²)   ⇒  P = 2*√((2.5 m)²+(1.25 m)²) = 5.59 m

⇒ R = A/P ⇒ R = 3.125 m²/5.59 m = 0.559 m

Substituting values into the Manning equation gives:

Q = (1/0.023)*(3.125 m²)*(∛(0.559 m)²)*(√0.025)

⇒ Q = 14.578 m³/s

8 0
3 years ago
Liquid water is fed to a boiler at 24°C and 10 bar is converted at a constant pressure to saturated steam.
zepelin [54]

We can find the change in the enthalpy through the tables A5 for Saturated water, pressure table.

For 1bar=1000kPa:

T_{sat}=179.88\°c

H_{fg} = 2014.6kJ/kg

c_p=4.18 kJkg^{-1}{K^{-1}

\nu_g = 0.19436m^3/kg

Replacing,

\Delta h = h_{fg}+c_p(T_{sat}-T_{inlet})

\Delta h = 2014.6+4.18(179.88-24)

\Delta h=2666.17kJ/kg

With the specific volume we know can calculate the mass flow, that is

\dot{m}=\frac{\frac{15000}{3600}}{0.19436}

\dot{m} = 21.4378kg/s

Then the heat required in input is,

Q=\dot{m}\Delta h

Q=21.4378*2666.17

Q=57157.036kW

With the same value required of 15000m^3/h, we can calculate the velocity of the water, that is given by,

V= \frac{\dotV}{A}

V = \frac{\frac{15000}{3600}}{\pi /4 *(0.15)^2}

V=235.79m/s

Finally we can apply the steady flow energy equation, that is

\dot{m}(h_1+\frac{V^2}{2000})+Q = \dot{m}h_2

Re-arrange for Q,

Q=\dot{m}(h_2-h_1-\frac{V^2}{2000})

Q=\dot{m}(\Delta h-\frac{V^2}{2000})

Q= (21.4378)(2666.17-\frac{235.79^2}{2000})

Q= 56560.88kW

We can note that consider the Kinetic Energy will decrease the heat input.

4 0
3 years ago
Given two alphabet strings str1 and str2. You can change the characters in str1 to any alphabet characters in order to transform
Keith_Richards [23]

Answer:

Explanation:

5

6 0
3 years ago
Energy that causes a transfer of heat between marterials
notsponge [240]

Thermal radiation is a form of heat transfer because the electromagnetic radiation emitted from the source carries energy away from the source to surrounding (or distant) objects.

I tried, but I hope this helps :)

4 0
3 years ago
According to OSHA standards, the air in the building that John works in is unsafe. The type of regulation that OSHA engages in i
ioda

Answer:

social regulation.

Explanation:

Social regulation are rules set aside to protect the environment or restrain activities that poses threat to public health and safety, examples includes environment pollution which includes lands, air, water etc, unhealthy work environment, etc. This rules identify activities that are allowed or under sanction for individuals, firms and government, breaking this rules most times comes with heavy fines or sanctions.

Social regulation help to see to the safety and well being of our environment, it serves as a guide for human activities.

7 0
3 years ago
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