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3 years ago

Why why why why why why why

Engineering

2 answers:

IceJOKER [234]3 years ago

6 0

Whyyyyyyyyyyywhyyyyyyyyyyywhyyyyyyy

Lorico [155]3 years ago

4 0

Whyyyyyttyyyyshdgeydgteegegegeyegeh

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The constant A in Equation 17.2 is 12π4 R/5(θD) 3 where R is the gas constant and θD is the Debye temperature (K). Estimate θD f

kirill115 [55]

Answer:

The Debye temperature for aluminum is 375.2361 K

Explanation:

Molecular weight of aluminum=26.98 g/mol

T=15 K

The mathematical equation for the specific heat and the absolute temperature is:

$C_{v} =AT^{3}$

Substituting in the expression of the question:

$C_{v} =(\frac{12\pi ^{4}R }{5\theta _{D}^{3} } )T^{3}$

$\theta _{D} =(\frac{12\pi ^{4}RT^{3} }{5C_{v} } ) ^{1/3}$

Here

$C_{v} =4.6\frac{J}{kg-K} *\frac{1kg}{1000g} *\frac{26.98g}{1mol} =0.1241J/mol-K$

Replacing:

$\theta _{D} =(\frac{12\pi ^{4}*8.31*15^{3} }{5*0.1241} )^{1/3} =375.2361K$

3 0

3 years ago

A single crystal of zinc is oriented for a tensile test such that its slip plane normal makes an angle of 65 degree with the ten

Crank

Answer:

a. 30°

b. 0.9MPa

Explanation:

The slip will occur along that direction for which the Schmid factor is maximum. The three possible slip directions are mentioned as 30°, 48°, 78°

The cosines for the possible λ values are given as

For 30°, cos 30 = 0.867

For 48°, cos 48 = 0.67

For 78°, cos 78 = 0.21

Among the three-calculated cosine values, the largest cos(λ) gives the favored slip direction

The maximum value of Schmid factor is 0.87. Thus, the most favored slip direction is 30° with the tensile axis.

The plastic deformation begins at a tensile stress of 2.5MPa. Also, the value of the angle between the slip plane normal and the tensile axis is mentioned as 65°

Thus, calculate the value of critical resolved shear stress for zinc:

From the expression for Schmid’s law:

τ = σ*cos(Φ)*cos(λ)

Substituting 2.5MPa for σ, 30° for λ and 65° for Φ

We obtain The critical resolved shear stress for zinc, τ = 0.9 MPa

4 0

3 years ago

If you install special sound-reflecting windows that reduce the sound intensity level by 33.0 dBdB , by what factor have you red

Sever21 [200]

Answer:

The sound intensity is reduced by a factor of 1995.26

Explanation:

When comparing two sound intensities, the intensity level is measured in the unit of decibel or dB. The intensity of the threshold of hearing for a human being is 10^−12 W/m^2 . When the intensity level is zero, it means that the sound intensity is the same as the threshold of hearing.

The reduced sound intensity level is given as 33 dB, so

10 log (I/Io) = - 33

I : intensity of the sound

Io ( = 10^−12 W/m^2): threshold of hearing

So, the intensity ratio is

I/Io = 10^-3.3

= 5.01 x 10^-4

1/ 5.01 x 10^-4 = 1995.26

3 0

4 years ago

This lab will require a power supply but what kind of power supply? This will be very important to the lab as the wrong power su

REY [17]

Answer:

The correct answer will be "DC". The further explanation is given below.

Explanation:

Ohm's law, that also specifies that perhaps the flow of current via the capacitor is equal to the PD (potential difference) between the opposite edges including its conductor while the heat, as well as the other physical state of that same conductor, stay the very same. Throughout the experiment, this linear change in electrical current with such a PD is better identified by changing the difference unidirectional.

⇒ $Instantaneous \ current =\frac{Instantaneous \ potential \ difference}{Resistance}$

The linear or dimensional dependency of current onto PD wasn’t simple and easy to grasp. The supply voltage used would also be DC tube.

3 0

3 years ago

Find x when ln2x=ln4

avanturin [10]

Answer:

x=\ln(2)\approx 0.693147181 please mark as brainliest

4 0

3 years ago