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Flura [38]
4 years ago
6

Lina packs 3-inch cups into boxes measuring 12 inches by 15 inches . How many cups fit in one box

Mathematics
1 answer:
Dahasolnce [82]4 years ago
5 0

Answer:

The answer is 60 cups

Step-by-step explanation:

First you need to find the area of the box which would be

12in x 15in =180in

The second step wpuld be to divide the area of the box by how tall the cups are

180/3 = 60

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(a) The third side could be 6 cm long because the rule for this triangle is that the third side must be greater than 1 and less than 7. (4 - 3 = 1; 4 + 3 = 7) Then you can draw the triangle with Side 1 = 3 cm; Side 2 = 4 cm; Side 3 = 6 cm.

(b) The third side could not be 1 cm long because the rule for this triangle is that the third side must be greater than 1 and less than 7. (4 - 3 = 1; 4 + 3 = 7) This means that you cannot draw the triangle.

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Which expression best represents the phrase"7 less than the quotient of 2x and 5"
vichka [17]

Answer:

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Step-by-step explanation:

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The equation of line m is 3x−5y=−4.
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8 0
4 years ago
Suppose that 60 batteries are shipped to an auto parts store, and that 5 of those are defective. A fleet manager then buys 6 of
PIT_PIT [208]

Answer:

In 8910 ways can at least 4 defective batteries be included in the purchase

Step-by-step explanation:

The order in which the batteries are there is not important, which means that the combinations formula is used to solve this question.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

In this question:

4 defective:

4 defective from a set of 5 and 2 non-defective from a set of 60 - 5 = 55. So

C_{5,4}C_{60,2} = \frac{5!}{1!4!} \times \frac{60!}{2!58!} = 8850

5 defective:

5 defective from a set of 5 and 1 non-defective from a set of 60 - 5 = 55. So

C_{5,5}C_{60,5} = \frac{5!}{0!5!} \times \frac{60!}{1!59!} = 60

In how many ways can at least 4 defective batteries be included in the purchase?

T = 8850 + 60 = 8910

In 8910 ways can at least 4 defective batteries be included in the purchase

8 0
3 years ago
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