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yulyashka [42]
3 years ago
11

You roll 2 dice. how likely is it that the 2 numbers will add up to 12 or less?

Mathematics
2 answers:
VashaNatasha [74]3 years ago
5 0
It is a very high probability. If you role two dice no matter what you will get 12 or less.
pochemuha3 years ago
5 0
It's a 100% chance that the 2 numbers will add up because the highest it can go to is 12, and you said that it's 12 or less, which is all the numbers.
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The Polygons below are similar find the value of x and y
balandron [24]

Answer:

x=49\degree,y=6

Step-by-step explanation:

Angle x corresponds to the complement of the 41\degree in the bigger triangle. See diagram in attachment.

This implies that,

x=90-41=49\degree


Also since the triangles are similar, the sides are in the same proportion.

This implies that,

\frac{3y-8}{15}=\frac{4}{6}


We multiply both sides by 15 to get,

3y-8=\frac{4}{6}\times 15


\Rightarrow 3y-8=\frac{2}{3}\times 15


\Rightarrow 3y-8=10


\Rightarrow 3y=10+8


\Rightarrow 3y=18


We divide through by 3 to get,

y=6


The correct answer is D

6 0
3 years ago
A customer buys four products priced at $18, $22, $35 and $40 from the same store. The customer returns the most expensive produ
SVETLANKA909090 [29]
Cost of most expensive product = $40

total money spent at the store
= 18 + 22 + 35
= 75
4 0
3 years ago
Read 2 more answers
These box plots show the prices for two different brands of shoes.
nignag [31]

Answer: Choice C

The interquartile range (IQR) for brand A, $10, is less than the IQR for brand B, $20.

===========================================================

Explanation:

Let's go through the answer choices one by one to see which is true and which is false. Also, we'll see which is helpful when it comes to the spread.

----------------------

Choice A

The IQR is found by subtracting the values of Q1 and Q3, which are the left and right edges of the box in that order.

For boxplot A, we have an IQR = Q3-Q1 = 80-70 = 10.

So we can immediately rule out choice A because the IQR for boxplot A is not 20, but instead it's 10.

----------------------

Choice B

The statement made in choice B is true, since the center vertical lines represent the median, but it's not useful to determine the spread. The median only tells us the center of the distribution. It doesn't tell us how spread out the distribution is.

Imagine you didn't have access to the graph. Now if you're told that the median for brand A is larger than brand B's median, then you'd probably think boxplot A is more spread out; however, the boxplot diagram shows the opposite is the case.

So again the median isn't used here. We can rule out choice B.

----------------------

Choice C

This statement is true. We subtract the box edge values to get the IQR values for each boxplot

For brand A we have IQR = Q3-Q1 = 80-70 = 10

For brand B we have IQR = Q3-Q1 = 70-50 = 20

This is the answer we're after.

The IQR is one tool we can use to measure the spread. The range is another option. We could also use the variance or the standard deviation (two slightly similar ideas) to measure the spread.

As you can see from the diagram, the larger the IQR, the more spread out the data will be.

----------------------

Choice D

This is false because earlier we've shown 10 is the IQR for brand A.

7 0
3 years ago
A pole that is 2.5 m tall casts a shadow that is 1.47 m long. At the same time, a nearby tower casts a shadow that is 36.25 m lo
Roman55 [17]

The tower is 61.65 meters tall.

<u>SOLUTION: </u>

Given that, a pole that is 2.5 m tall casts a shadow that is 1.47 m long.  

At the same time, a nearby tower casts a shadow that is 36.25 m long.  

We have to find height of the tower.  

Now, we know that,

2.5 \mathrm{m} \text { tall } \rightarrow 1.47 \text { long shadow }

Then, (let it be) n meter tall \rightarrow 36.25 long shadow

So, by cross multiplication method,

\Rightarrow \frac{2.5}{1.47}=\frac{n}{36.25}

This can be written as,

\Rightarrow 36.25 \times 2.5=1.47 \times n \rightarrow 1.47 n=90.625 \rightarrow n=61.649 \rightarrow n=61.65 \text{ m}

Cross multiplications steps: (To find Single Variable)

  1. Multiply the numerator of the left-hand fraction by the denominator of the right-hand fraction.
  2. Multiply the numerator of the right-hand fraction by the denominator of the left-hand fraction.
  3. Set the two products equal to each other.
  4. Solve for the variable.
6 0
3 years ago
Write 177 as a decimal, rounded to the nearest hundredth.
jek_recluse [69]

Answer:

1.77 is the answer.

hope u got it

3 0
3 years ago
Read 2 more answers
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