Nolan and his children bought fruits (Apples and bananas) worth $8.
Cost of each apple and bananas are $2 and $0.40 respectively.
Let the number of bananas he bought = y
And the number of apples = x
Therefore, cost of the apples =$2x
And the cost of bananas = $0.40y
Total cost of 'x' apples and 'y' bananas = $(2x + 0.40y)
Equation representing the total cost of fruits will be,
(2x + 0.40y) = 8
10(2x + 0.40y) = 10(8)
20x + 4y = 80
5x + y = 20 --------(1)
If he bought 5 times as many bananas as apples,
y = 5x ------(2)
Substitute the value of y from equation (2) to equation (1),
5x + 5x = 20
10x = 20
x = 2
Substitute the value of 'x' in equation (2)
y = 5(2)
y = 10
Therefore, Nolan bought 2 apples and 10 bananas.
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Answer:
+
Step-by-step explanation:
938 + 347 = 1285
2007 - 1285 = 722
CHECK:
938 + 347 + 722 = 2007
D' = (-2, 0) = 2*(-1, 0) = 2*D
The scale factor is 2.
