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alexgriva [62]
3 years ago
10

How much is 8y equal feet

Mathematics
1 answer:
trasher [3.6K]3 years ago
8 0
I think it would be 2.67
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Find m<1 and find m<2
xenn [34]

Answer:

m∠1 = 50°

m∠2 = 130°

Explanation:

m∠2 = 130° because of alternate exterior angles.

m∠1 = 50° because it is supplementary to m∠2. So, 180 - 130 = 50.

8 0
3 years ago
Here are the questions:
yaroslaw [1]

Answer:

Q1) 0.46 Q2)0.2333

Step-by-step explanation:

Q1) P=(4+12+7)/50 =0.46

Q2) P=7/(4+7+10+9)

6 0
3 years ago
Triangle ABC has vertices of A(-6, 7), B (4, -1), and C (-2, -9). What is the length of the median from angle B?
jeka94
Coordinates of the midpoint of AC:
M ( (-6-2) / 2) , ( 7-9 ) /2 ) = ( -4, -1 )
d ( BM ) = √ ( 4 + 4 )² + ( -1+ 1 )²
d ( BM ) =   √  8 ²  =√ 64 = 8
The length of the median from angle B is 8.
6 0
3 years ago
Read 2 more answers
Triangle ABC has vertices at A(−1 , 2), B(4, 2), and C(3, −1). Classify the triangle according to the side lengths.
Orlov [11]

Answer:

B) Isosceles

Step-by-step explanation:

The given triangle has vertices at A(-1,2), B(4,2) and C(3,-1).

We must first determine the length of the sides of the triangle, before we can classify it.

We apply the distance formula to find length of the sides.

|AB|=\sqrt{(4--1)^2+(2-2)^2}

\Rightarrow |AB|=\sqrt{(4+1)^2+(2-2)^2}

\Rightarrow |AB|=\sqrt{5^2+(0)^2}

\Rightarrow |AB|=\sqrt{25}

\Rightarrow |AB|=5 units.

The length of side BC

|BC|=\sqrt{(3-4)^2+(-1-2)^2}

\Rightarrow |BC|=\sqrt{(-1)^2+(-3)^2}

\Rightarrow |BC|=\sqrt{1+9}

\Rightarrow |BC|=\sqrt{10}

The length of side AC

|AC|=\sqrt{(3--1)^2+(-1-2)^2}

We simplify to obtain;

|AC|=\sqrt{(3+1)^2+(-3)^2}

\Rightarrow |AC|=\sqrt{(4)^2+(-3)^2}

|AC|=\sqrt{16+9}

|AC|=\sqrt{25}

|AC|=5\:units

Since |AC|=5\:units=|AB|, the given triangle is an isosceles triangle.

The correct answer is

6 0
3 years ago
Read 2 more answers
√85 between which two intergers ​
lilavasa [31]

Answer:

I think that it is 9 and 10 because when you simply the number 85 it would be 9.21 which is round by 9

7 0
3 years ago
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