Simplify it for me please Simplify: 1.50
1 answer:
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The inclination to the nearest tenth of a degree exists 0.24146
<h3>What is the inclination to the nearest tenth of a degree?</h3>
The given scenario includes a right-angled triangle where the length of the ramp exists hypotenuse and the rise of ramp exists the perpendicular.
Given: H = 4.6 m and P = 1.1 m
We have to use the trigonometric ratios to find the angle. The ratio that has to be used should involve both perpendicular and hypotenuse
Let x be the angle then
sin x = P/H
sin x = 1.1/4.6
sin x = 0.23913
= 0.24146
The inclination to the nearest tenth of a degree exists 0.24146
To learn more about trigonometric ratios refer to:
#SPJ9
Let 'n' be the number of side of a regular polygon each angle are equal and sum of each angle equal to (n-2)×180. ∴For a regular pentagon have five equal side, n=5
∴ sum of each angle = (n-2)×180=3×180 = 540. and ecah angle = 540÷5=108°. Therefore ∠BCG = 108° and ∠ABC =108°
Here BE is one of the diagonal of regular pentagon ABCDE. BE divide ∠ABC in 1:2 ratio
Therefore ∠ABE : ∠CBE = 36: 72
∴ ∠GCB + ∠CBE = 108° +72°=180°