Answer:
yes
Step-by-step explanation:
lets use a significance level of = 0.1
<u> Determine if the sequence indicates randomness </u>
First step :
H0 : pattern is random
H1 : pattern not random
n1 ( number of true answers ) = 10
n2 ( number of false answers ) = 10
also number of runs for T = 5
number of runs for F = 5
Total number of runs = 5+ 5 = 10
Given that critical value at 0.05 = 23
we will reject the null hypothesis ( i.e the sequence departs from randomness )
0.7777777778
don't you have calculators or internet, you could easily find your question on internet
Answer:
2.547
Step-by-step explanation:
2pir=8
1.273=r
d=2r
2.547=d
The correct answer is a. 3125
That's because the letter can be used more than once, so if you start and try everything from aaaaa, to ttttt, the possibilities are huge and much larger than any of the lower numbers.
