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mihalych1998 [28]

3 years ago

6

What does “ Classify each polynomial by degree and number of terms” mean?

1 answer:

MrMuchimi3 years ago

3 0

Okay so I'm going to try and explain it to you as best as possible. So all they are basically telling you is to give it a name. A degree on a polynomial is the highest exponent on it and the number of terms is the number of numbers. For example: -5x^3 + 2x^2 - 7
This is a 3rd degree polynomial with 3 terms. All you have to do is look at the largest exponent and that is your degree and the number of numbers.

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Lady_Fox [76]

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Fine the length of the hypotenuse of a Right triangle with legs pf 20cm and21cm

Arisa [49]

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3 years ago

What is the following sum? 2 (RootIndex 3 StartRoot 16 x cubed y EndRoot) 4 (RootIndex 3 StartRoot 54 x Superscript 6 Baseline y

san4es73 [151]

Equivalent expressions are expressions that have the same value, and can be used interchangeably.

The result of the sum $2 (\sqrt[3]{16x^3y}) + 4 (\sqrt[3]{54x^6y^5})$ is $4x\sqrt[3]{2y} + 8x^2y\sqrt[3]{2y^2})$

The expression is given as:

$2 (\sqrt[3]{16x^3y}) + 4 (\sqrt[3]{54x^6y^5})$

Rewrite the expression as:

$2 (\sqrt[3]{16x^3y}) + 4 (\sqrt[3]{54x^6y^5}) = 2 (\sqrt[3]{2^4x^3y}) + 4 (\sqrt[3]{3^3 \times 2x^6y^5})$

Evaluate the roots

$2 (\sqrt[3]{16x^3y}) + 4 (\sqrt[3]{54x^6y^5}) = 2 (2x\sqrt[3]{2y}) + 4 (3x^2y\sqrt[3]{2y^2})$

Open the brackets

$2 (\sqrt[3]{16x^3y}) + 4 (\sqrt[3]{54x^6y^5}) = 4x\sqrt[3]{2y} + 12x^2y\sqrt[3]{2y^2})$

The above expression cannot be further simplified.

Hence, the result of the sum $2 (\sqrt[3]{16x^3y}) + 4 (\sqrt[3]{54x^6y^5})$ is $4x\sqrt[3]{2y} + 8x^2y\sqrt[3]{2y^2})$

Read more about equivalent expressions at:

brainly.com/question/2972832

7 0

2 years ago

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