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3 years ago

Find the slope and y-intercept of the line with equation 2y+x=-6

Mathematics

2 answers:

Step2247 [10]3 years ago

5 0

Answer:

Step-by-step explanation:

rearrange this equation into slope-intercept form(y=mx+b)

2y=-6-x

y=-3-x/2

y=-1/2*x-3

m is the slope

b is the y-int

slope=1/2

y-int= -3

ratelena [41]3 years ago

4 0

mx+b

b is the y-int

2y=-6-x

y=-3-x/2

y=-1/2*x-3

slope=1/2

y-int= -3

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Ludmilka [50]

Answer:

2.5 teaspoon.

Step-by-step explanation:

4 serve recipe need cinnamon = 1 tsp

1 serve recipe need cinnamon = 1/4 tsp

10 serve recipe need cinnamon = 1/4 * 10

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3 years ago

Write an expression that represents the product of q and 8, divided by 4.

Sholpan [36]

Answer:

8 q / 4 =2q

Step-by-step explanation

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3 years ago

A journal article reports that a sample of size 5 was used as a basis for calculating a 95% CI for the true average natural freq

oksano4ka [1.4K]

Answer:

$Lower = 231.134- 3.098=228.036$

$Upper = 231.134+ 3.098=234.232$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

s represent the sample standard deviation

n=5 represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

And for this case we know that the 95% confidence interval is given by:

$\bar X=\frac{233.002 +229.266}{2}= 231.134$

And the margin of error is given by:

$ME = \frac{233.002 -229.266}{2}= 1.868$

And the margin of error is given by:

$ME= t_{\alpha/2} \frac{s}{\sqrt{n}}$

The degrees of freedom are given by:

$df = n-1 = 5-1=4$

And the critical value for 95% of confidence is $t_{\alpha/2}= 2.776$

So then we can find the deviation like this:

$s = \frac{ME \sqrt{n}}{t_{\alpha/2}}$

$s = \frac{1.868* \sqrt{5}}{2.776}= 1.506$

And for the 99% confidence the critical value is: $t_{\alpha/2}= 4.604$

And the margin of error would be:

$ME = 4.604 *\frac{1.506}{\sqrt{5}}= 3.098$

And the interval is given by:

$Lower = 231.134- 3.098=228.036$

$Upper = 231.134+ 3.098=234.232$

6 0

3 years ago

In imaginary numbers can you multiply two radicals that have negative values under them that do not square to whole numbers

ElenaW [278]

Yes, you can; based on the inherent assumption that the "two radicals that have negative values" are, in fact, "imaginary numbers" .

Take, for example, the commonly known "imaginary number": "i" ; which represents the "imaginary number" ; " √-1 " .

Since: "i = √-1" ;

Note that: " i² = (√-1)² = √-1 * √-1 = √(-1*-1) = √1 = 1 .
__________________________________________________

7 0

3 years ago

Read 2 more answers

Please help me please

sveticcg [70]

Answer:

Step-by-step explanation:

If you need any explanation you can communicate with me

4 0

3 years ago