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3 years ago

Help me please .....

Physics

1 answer:

Ahat [919]3 years ago

3 0

Answer: 80N (choice #4)

Explanation: The force of gravity is proportional to the inverse of the square of the distance. That means, if the distance is cut in half, the square of that is 1/4, and the inverse of that is a factor 4. So the force increases by a factor of 4. Given that the force is 20N, the new force will be 4*20N=80N.

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What’s the velocity of a ball falling with 100 joules of kinetic energy and a mass of 2 kilograms

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Answer:

the velocity is 10 m/s

Explanation:

Using the expression for kinetic energy we have:

$Ek=\frac{1}{2} *m*v^{2} \\\\Ek=100J\\m=2kg\\v=\sqrt{(2*100/2)}\\ v=10[m/s]$

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3 years ago

Is Smoke Abiotic or Biotic?

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Answer: Smoke is Abiotic because it is not a living thing.

Explanation: Hopefully this helps u. Have a great rest of your day. I hope this is the right answer

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3 years ago

An object of mass 30KG is falling in air and experiences a force due to air resistance of 50 newtons determine the net force act

ryzh [129]

Answer:

Assume that $g = 10\; \rm N \cdot kg^{-1}$ . The net force on this object will be $250\; \rm N$ (downwards.) The acceleration of this object will be approximately $8.3\; \rm m \cdot s^{-2}$ (also downwards.)

Explanation:

<h3>Net force</h3>

The object is falling towards the ground because of gravity. The size of the gravitational force on this object depends on its mass and the strength of the gravitational field at its location.

Near the surface of the earth, the gravitational field strength is approximately $10\; \rm N \cdot kg^{-1}$ . In other words, approximately $10\; \rm N$ of gravitational force acts on each kilogram of mass near the surface of the earth.

The mass of this object is given as $m = 30\; \rm kg$ . Therefore, the size of the gravitational force on it will be:

$W = m \cdot g \approx 30 \; \rm kg \cdot 10\; N \cdot kg^{-1} = 300\; \rm N$ .

Near the surface of the earth, gravitational forces point towards the ground. On the other hand, the direction of air resistance on this object will be opposite to its direction of motion. Since this objects is moving towards the ground, the air resistance on it will be directed in the opposite direction. That's exactly the opposite of the direction of the gravitational force on this object. The net force on this object will be:

$300\; \rm N - 50\; \rm N =250\; \rm N$ .

<h3>Acceleration</h3>

Let $a$ denote the acceleration on this object. Apply Newton's Second Law of motion:

$\begin{aligned} a &= \frac{F(\text{net force})}{m} \approx \frac{250\; \rm N}{30\; \rm kg} \approx 8.3\; \rm m \cdot s^{-2}\end{aligned}$ .

Note that the acceleration of this object and the net force on it should be in the same direction.

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3 years ago

g The ant has traveled 10 cm horizontally and 6 cm vertically from its starting point on a twig with a slope of 0.5. If this is

snow_tiger [21]

Answer:

a) a right triangle, b) x = 0.167 m

Explanation:

a) It is asked to find which geometry figure describes the movement of the ant.

Let's use trigonometry with the angles measured in radians

tan θ = y / x

tan θ = 6/10

θ = tan⁻¹ 0.6

θ = 0.54 rad

this value is equal to the upward slope therefore the geometric body that describes the movement is a right triangle

b) it is asked to find the horizontal displacement for a vertical displacement of y = 0.1 cm x = y / tan tea

x = 0.1 / tan 0.54

x = 0.1668 m

x = 0.167 m

6 0

3 years ago