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insens350 [35]
3 years ago
13

True or false is Conservation of monestum is the same as Conservation of energy

Physics
1 answer:
fiasKO [112]3 years ago
3 0

Answer:

Conservation of Energy: the total energy of the system is constant. Conservation of Momentum: the mass times the velocity of the center of mass is constant. Conservation of Angular Momentum: The total angular momentum of the system is constant.

Explanation:

none

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A 4.88 x 10-6 C charge moves 265 m/s
Alex73 [517]

Answer:

F=0N

Explanation:

From the question we are told that:

Charge Q=4.88 x 10-6 C

Velocity v= 265m/s

Angle \theta =0 \textdegree

Magnetic field B=0.0579T

Generally the equation for Force is mathematically given by

 F=Q(\=v*\=B)

 F=qvBsin\theta

Therefore

 F=qvBsin0 \textdegree

 F=0N

5 0
3 years ago
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7 0
2 years ago
A 4.00 m long, massless beam rests horizontally on a support 3.00 m from the left
Rus_ich [418]

If the beam is in static equilibrium, meaning the Net Torque on it about the support is zero, the value of x₁ is 2.46m

Given the data in the question;

  • Length of the massless beam;L = 4.00m
  • Distance of support from the left end; x = 3.00m
  • First mass; m1 = 31.3 kg
  • Distance of beam from  the left end( m₁ is attached to ); x_1 = ?
  • Second mass; m_2 = 61.7 kg
  • Distance of beam from  the right of the support( m₂ is attached to ); x_1 = 0.273m

Now, since it is mentioned that the beam is in static equilibrium, the Net Torque on it about the support must be zero.

Hence, m_1g( x-x_1) = m_2gx_2

we divide both sides by g

m_1( x-x_1) = m_2x_2

Next, we make x_1, the subject of the formula

x_1 = x - [ \frac{m_2x_2}{m_1} ]

We substitute in our given values

x_1 = 3.00m - [ \frac{61.7kg\ * \ 0.273m}{31.3kg} ]

x_1 = 3.00m - 0.538m

x_1 = 2.46m

Therefore, If the beam is in static equilibrium, meaning the Net Torque on it about the support is zero, the value of x₁ is 2.46m

Learn more; brainly.com/question/3882839

6 0
3 years ago
To pop a balloon you stab it with a pencil. If the area of the pencil tip is .01 cm² and the pressure applied by the pencil to t
Romashka-Z-Leto [24]

Answer:

Push with force of 1N

Explanation:

I have explained in the paper.

Goodluck

3 0
3 years ago
Can y'all please help me out with this ?
Inessa05 [86]

Answer:

no where is the main part of the question dude

3 0
3 years ago
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