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2 years ago

What do I do here pls help

Mathematics

1 answer:

guajiro [1.7K]2 years ago

5 0

Answer:

Step-by-step explanation:

Is this a trick question or error?

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What isn't the bets approximation for the area of this circle labeled 8 inches use3.14 to approximate pi

Arte-miy333 [17]

Answer:

50.272 in^2

Step-by-step explanation:

Step one:

Given data

Circles are described using the diameter parameter

Diameter of the circle is 8 inches

radius = 4 inche= d/2

Step two:

The area of the circle is

A= πr^2

A= 3.142*4^2

A=3.142*16

A=50.272 in^2

8 0

3 years ago

Which fraction is equivalent to -(3/4)?

Alekssandra [29.7K]

Answer:

I dont understand the context of the question but something eqqual to that would be -6/8

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

If f(x) = 9x10 tan−1x, find f '(x).

djverab [1.8K]

Answer:

$\displaystyle f'(x) = 90x^9 \tan^{-1}(x) + \frac{9x^{10}}{x^2 + 1}$

General Formulas and Concepts:

Calculus

Differentiation

Derivatives
Derivative Notation

Derivative Property [Multiplied Constant]: $\displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)$

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Derivative Rule [Product Rule]: $\displaystyle \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)$

Step-by-step explanation:

Step 1: Define

Identify

$\displaystyle f(x) = 9x^{10} \tan^{-1}(x)$

Step 2: Differentiate

[Function] Derivative Rule [Product Rule]: $\displaystyle f'(x) = \frac{d}{dx}[9x^{10}] \tan^{-1}(x) + 9x^{10} \frac{d}{dx}[\tan^{-1}(x)]$
Rewrite [Derivative Property - Multiplied Constant]: $\displaystyle f'(x) = 9 \frac{d}{dx}[x^{10}] \tan^{-1}(x) + 9x^{10} \frac{d}{dx}[\tan^{-1}(x)]$
Basic Power Rule: $\displaystyle f'(x) = 90x^9 \tan^{-1}(x) + 9x^{10} \frac{d}{dx}[\tan^{-1}(x)]$
Arctrig Derivative: $\displaystyle f'(x) = 90x^9 \tan^{-1}(x) + \frac{9x^{10}}{x^2 + 1}$