3 years ago

What do I do here pls help

Mathematics

1 answer:

guajiro [1.7K]3 years ago

5 0

Answer:

Step-by-step explanation:

Is this a trick question or error?

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Given that a:b:c= 20 : 35 : 15, a) simplify a : b:c, b) find a:b,

Furkat [3]

Answer:

a) 4:7:3

b) 4:7 / 20:35

c) 3:7 / 15:35

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2 years ago

Kelsey has already spent 42 minutes on the phone, and she expects to spend 2 more minutes

grandymaker [24]

Answer:

11 calls

Step-by-step explanation:

She has already spent 42 min. Also she wants to talk for 2 min per call. We can change calls on x. So, only 2x min for her calls left.

42 + 2x = 64

2x = 64 - 42

2x= 22

x=11

Answer: 11 calls

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3 years ago

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Westkost [7]

the correct answer would be 4 3/4

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3 years ago

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Delvig [45]

Answer:

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Step-by-step explanation:

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3 years ago

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A variable force of magnitude F(x) moves a body of mass m along the x-axis from x1 to x2. The net work done by the force in movi

kicyunya [14]

Answer:

$w=\frac{1}{2}m(v^2_2-v^2_1)$

Step-by-step explanation:

We are given that a variable force of magnitude F(x) moves a body along the x- axis from $x_1$ to $x_2$ .

The net work done by the force in moving the body from $x_1$ to $x_2$ .

$v_1$ =Velocity of the body at $x_1$

$v_2=$ Velocity of the body at $x_2$

We know that

Work done=Final kinetic energy-Initial kinetic energy

$w=\frac{1}{2}mv^2_2-\frac{1}{2}mv^2_1$

K.E= $\frac{1}{2}mv^2$

$Net\;work \;done=\frac{1}{2}m(v^2_2-v^2_1)$

Hence, the net work done by the force is given by

$w=\frac{1}{2}m(v^2_2-v^2_1)$

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3 years ago