Which of the following best illustrates the role that gravity played in the formation of the solar system?

Physics

1 answer:

Inga [223]3 years ago

6 0

<h3><u>Answer;</u></h3>

D. Gravity pulled particles of dust and gas together to form planets.

<h3><u>Explanation;</u></h3>

<em><u>The formation of the solar system took place about 4.6 billion years ago when gravity pulled together low-density cloud of interstellar gas and dust. In other words gravity pulled dust and gas particles together to form planets.</u></em>
It is believed that the solar system formed from an explosion that caused a disturbance of cloud of gas and dust in space. The explosion formed waves that squeezed the cloud and dust particles. Squeezing made the cloud start to collapse, as gravity pulled the gas and dust together, forming a solar nebula and then planets were formed.
<em><u>Gravity is important as It keeps the solar system together because without it the planets including the earth would be floating around.</u></em>

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What should be the spring constant k of a spring designed to bring a 1200 kg car to rest from a speed of 85 km/h so that the occ

borishaifa [10]

Answer:

k = 5178.8 N/m

Explanation:

As we know that spring mass system will oscillate at angular frequency given as

$\omega = \sqrt{\frac{k}{m}}$

now we have

$\omega = \sqrt{\frac{k}{1200}}$

now the maximum acceleration of the spring block system is at its maximum compression state which is given as

$a = \omega^2 A$

here A= maximum compression of the spring

so here in order to find maximum compression of the spring we will use energy conservation as we know that initial total kinetic energy of the car will convert into spring potential energy

$\frac{1}{2}mv^2 = \frac{1}{2}kA^2$

here we know that

v = 85 km/h

$v = 85 \times\frac{1000}{3600} = 23.61 m/s$

now we have

$(1200)(23.61^2) = kA^2$

$A^2 = \frac{6.68 \times 10^5}{k}$

now from above equation of acceleration we have

$5.0 g = (\frac{k}{m})\sqrt{\frac{6.68 \times 10^5}{k}}$

$5.0(9.81) = \sqrt{k}(0.68)$

$k = 5178.8 N/m$

6 0

3 years ago

A moving rope (parallel to the slope) is used to pull skiers up the mountain. If the slope of the hill is 37" and friction is ne

Charra [1.4K]

Since rope is parallel to the inclined plane so here we can say that net force parallel to the person which is pulling upwards must counterbalance the component of weight of the person.

Now here we will do the components of the weight of the person

given that weight of the person = 500 N

now its components are

$W_x = 500 cos37$