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RUDIKE [14]
3 years ago
14

A sound that's produced by a single wave at a constant frequency and with no overtones is called

Physics
1 answer:
notka56 [123]3 years ago
7 0
It is called a pure sound
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Calculate the pressure exerted on the heel of a boy’s foot if the boy weighs 80 N and he lands on one heel,which has an area of
cricket20 [7]

Pressure at a given surface is given as ratio of normal force and area

so here force due to heel of the shoes is given as 80 N

and the area of the heel is given as 16 cm^2

so we can say

P = \frac{F}{A}

here we have

F = 80 N

A = 16 cm^2 = 16 * 10^{-4} m^2

P = \frac{80}{16 * 10^{-4}}

P = 5 * 10^4 N/m^2

so pressure at the surface due to its heel will be 5 * 10^4 N/m^2

3 0
3 years ago
Jessica jogs on a path that is 25 km long to get to the park that is south of the jogging path if it takes just a cut 2.5 hours
Vinil7 [7]

Answer:

10km/h

Explanation:

25÷2.5=10

speed = distance/time

velocity is a magnitude and needs a direction which wasnt provided so its basically the same as the speed

8 0
3 years ago
What type of noise is most difficult to remove from a digital signal? why?
Lilit [14]
Interference if the hardest to remove due to the superposition of the frequencies of the radio waves
8 0
3 years ago
Two spaceships that have different masses but rocket engines of identical force are at rest in space. if they fire their rockets
NISA [10]
Force is calculated F=m×a.
If both ships speed up with the same force, but have a different mass, This means that a also has to be different. If F is the same but ship a has a bigger mass(m) than ship b, then the acceleration(a) of ship b has to be bigger so F of each ship is the same. So the ship with the smaller mass will speed up faster.
5 0
3 years ago
A viola string with a fundamental frequency of D4 (293 Hz) is generally tuned using a tension of 49.0 N. However, just before a
Alborosie

Answer:

Explanation:

For fundamental frequency in a vibrating string , the formula is

n = 1 / 2L  x  √ ( T /m₁ )

n is frequency , L is length , T is tension and m₁ is mass per unit length .

For first string ,

293 =  1 / 2L  x  √ ( 49 N  /m₁ )

For second string , let mass per unit length be m₂ .

196 =  1 / 2L  x  √ ( 49 N  /m₂ ) ------ ( 1 )

To bring its frequency back to previous one let tension be T

293  =  1 / 2L  x  √ ( T  /m₂ ) ------- ( 2 )

Dividing

293 / 196 = √ ( T  /49  )

1.4948 = √ ( T  /49  )

2.2344 = T  /49

T = 109.48 N .

8 0
2 years ago
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