All categories

3 years ago

Neglecting losses in a transformer, it's input and output ______ are equal.

Physics

2 answers:

Mila [183]3 years ago

7 0

Neglecting losses in a transformer, it's input and output <em>power </em>are equal.<em> (C)</em>

Alex17521 [72]3 years ago

6 0

The input power in the transformer are equal to the output power of a transformer.

Answer : Option C

Explanation:

The transformers have power on either side as input or output to be constant. This is so because the transformers are the electrical device which transfer the energy between the circuits. There are two types of transformers, step up transformers and step down transformers.

Both follows the following expression of power = voltage x current. According to the type of transformer, the turns of wire and voltage and current are kept varying but the power remains constant.

You might be interested in

calculate how much charge passes through the LED in 1 hour if the current flowing in the circuit below is 350mA

Morgarella [4.7K]

Given the the current flowing in the circuit and the elapsed time, the charge that passes through the LED is 1260 Coulombs.

<h3>What is Current?</h3>

Current is simply the rate of flow of charged particles i.e electrons caused by EMF or voltage.

If a charge passes through the cross-section of a conductor in a given time, the current I is expressed as;

I = Q/t

Where Q is the charge and t is time elapsed.

Given the data in the question;

Time elapsed t = 1hr = 3600s

Current I = 350mA = 0.35A

Charge Q = ?

We substitute our given values into the expression above to determine the charge.

I = Q/t

Q = I × t

Q = 0.35A × 3600s

Q = 1260C

Therefore, given the the current flowing in the circuit and the elapsed time, the charge that passes through the LED is 1260 Coulombs.

Learn more about current here: brainly.com/question/3192435

#SPJ1

3 0

2 years ago

S GP A projectile of mass m moves to the right with a speed vi (Fig. P11.51a). The projectile strikes and sticks to the end of a

Andrews [41]

What is the kinetic energy of the system after the collision?

$K_f=\frac{3}{2} \frac{m^{2}v_i^{2} }{(M+3m)}$

How this is calculated?

Given:

Initial speed= $v_i$

mass of rod=M

Let, Initial kinetic energy = $K_i$

Final kinetic energy= $K_f$

Moment of inertia =I

What is the moment of inertia?

$I=(I_p)_0+(I_{rod})_0\\I=m(\frac{d}{2})^{2} +\frac{Md^{2} }{12} \\I=\frac{(M+3m)d^{2} }{12}$

What is the angular momentum?

By conservation of angular momentum,

$L_i=L_f$

$mv_i\frac{d}{2}=\frac{(M+3m)d^{2}\omega }{12} \\\omega=\frac{6mv_i^{2} }{d(M+3m)}$

We know that, the final kinetic energy is given by,

$K_f=I\omega^{2}\\K_f=\frac{1}{2} *\frac{(M+3m)d^{2} }{12} *\frac{36m^{2}v_i^{2}}{d^{2}(M+3m)^{2}}\\ K_f=\frac{3}{2} \frac{m^{2}v_i^{2} }{(M+3m)}$

What is the kinetic energy?

In physics, the kinetic energy of an object is the energy that it possesses due to its motion.
It is defined as the work needed to accelerate a body of a given mass from rest to its stated velocity.
Having gained this energy during its acceleration, the body maintains this kinetic energy unless its speed changes.

To know more about kinetic energy, refer:

brainly.com/question/114210

#SPJ4

8 0

1 year ago

Principle of electroplating

frosja888 [35]

dnxjjc cjgnjgjnffjnfkfmgkcknsmksjs dmxmcmfkcnfjcnfjfnfjf in jfnfifnfifnf

4 0

3 years ago

Read 2 more answers

During exercise, the amount of ____________ carried in the blood to the muscles increases.

ipn [44]

<span>The correct answer is: Oxygen

Explanation:
In order to function properly (movement etc.) during exercise, muscles require oxygen. During exercise, the depth as well as the rate of breathing increase, which in turn increases the amount of oxygen inhaled. In order to expand and contract lungs and for other bodily movements, muscles require oxygen, and for that, more oxygen is carried in the blood to muscles. Hence, the correct answer is Oxygen.</span>

8 0

3 years ago

Read 2 more answers

refrigerant 134a enters a compressor operating at steady state as saturated vapor at 0.12 MPa and exits at 1.2 MPa and 70 C at a

Afina-wow [57]

Answer:

the power input to the compressor is 7.19Kw

Explanation:

Hello!

To solve this problem follow the steps below.

1. We will call 1 the refrigerant state at the compressor inlet and 2 at the outlet.

2. We use thermodynamic tables to determine enthalpies in states 1 and 2.

(note: Through laboratory tests, thermodynamic tables were developed, these allow to know all the thermodynamic properties of a substance (entropy, enthalpy, pressure, specific volume, internal energy etc ..)

through prior knowledge of two other properties such as pressure and temperature. )

h1[quality=1, P=0.12Mpa)=237KJ/Kg

h2(P=1.2Mpa, t=70C)=300.6KJ/kg

3. uses the first law of thermodynamics in the compressor that states that the energy that enters a system is the same that must come out

Q=heat=0.32kJ/s

W=power input to the compressor

m=mass flow=0.108kg/S

m(h1)+W=Q+m(h2)

solving for W

W=Q+m(h2-h1)

W=0.32+0.108(300.6-237)=7.19Kw

the power input to the compressor is 7.19Kw

7 0

3 years ago