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3 years ago

150c passes through cell in 30 seconds. cell has a potential difference of 12v. what is current in the circuit

Physics

1 answer:

zzz [600]3 years ago

6 0

The current in the circuit is 5 A

Explanation:

The intensity of current is given by the equation:

$I=\frac{q}{t}$

where

I is the current

q is the amount of charge passing through a given point of the circuit in a time interval of t

For the cell in this problem, we have

q = 150 C is the charge

t = 30 s is the time interval

Substituting into the equation, we f ind

$I=\frac{150}{30}=5 A$

Learn more about current:

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A taxi is travelling at 15 m/s. Its driver accelerates with

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If we assume that the acceleration is constant, we can use on the kinematic equations:

Vf = Vi + a*t = 15 + 3*4 = 27 m/s

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3 years ago

A truck is using a hook to tow a car whose mass is one quarter that of the truck. If the force exerted by the truck on the car i

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Answer:

Force exerted by car on truck will be 6000 N in opposite direction

Explanation:

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According to newtons third law for any action there is equal and opposite reaction

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3 years ago

A wheel of moment of inertia of 5.00 kg∙m2 starts from rest and accelerates under a constant torque of 3.00 N∙m for 8.00 s. What

Strike441 [17]

Answer:

The wheel's rotational kinetic energy is 57.6 J.

Explanation:

Given that,

Moment of inertia = 5.00 kg.m²

Torque = 3.00 N.m

Time = 8.00 s

We need to calculate the angular acceleration

Using formula of the torque act on the wheel

$\tau=I\alpha$

$\alpha=\dfrac{\tau}{I}$

Where, I = moment of inertia

$\alpha$ = angular acceleration

$\tau$ = torque

Put the value into the formula

$\alpha=\dfrac{3.00}{5.00}$

$\alpha=0.6\ rad/s^2$

We need to calculate the final angular velocity

Initially wheel at rest so initial velocity is zero.

Using formula of angular velocity

$\alpha=\dfrac{\omega_{f}-\omega_{i}}{t}$

$\omega_{f}=\omega_{i}+\alpha t$

Put the value into the formula

$\omega_{f}=0+0.6\times8.00$

$\omega_{f}=4.8\ rad/s$

We need to calculate the rotational kinetic energy of the wheel

Using formula of the rotational kinetic energy

$K.E_{rot}=\dfrac{1}{2}I\omega^2$

$K.E_{rot}=\dfrac{1}{2}\times5.00\times(4.8)^2$

$K.E_{rot}=57.6\ J$

Hence, The wheel's rotational kinetic energy is 57.6 J.

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3 years ago

The device used to separate out different wavelengths of light from one another is a ?

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A spectrometer hopes this helps you out brainliest me ;)

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3 years ago

Heater has power rating of 500W inserted in 1Kg of water for half of a minute. Water was at 20 degrees Celsius. What is the temp

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Answer:

23.585°C

Explanation:

500W/s = 500J/s half a minute = 30s

30 x 500J = 15000J in half a minute

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Use the specific heat formula:

(20C)(1kg)(4184J/kgC)= 83680J

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98680J = (x)(1kg)(4184J/kgC)

98680J = 4184x

Divide

x = 23.585°C

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3 years ago