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3 years ago

When a spacecraft travels away from Earth, the gravitational force acting on it

2 answers:

6 0

The correct answer is decreases

The further away you are the weaker it would be. That's why at one point you stop being in the field and ti doesn't pull you towards it anymore. Proportionally, if you move towards the Earth then it increases.

Sindrei [870]3 years ago

4 0

Gravitational force on aircraft at some distance from the Earth is given as

$F = \frac{Gm_1m_2}{r^2}$

here we know that

$m_1$ = mass of Earth

$m_2$ = mass of aircraft

r = distance between center of earth and aircraft

now as the aircraft is flying away from the surface of Earth so here the distance between them is increasing with the motion of aircraft

So as it moves away the force between them will decrease

So here we can say that

When a spacecraft travels away from Earth, the gravitational force acting on it

<u>decreases</u>

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Along some shorelines, incoming waves cause the water to simply rise and fall rather that form a surf zone. What does this tell

NARA [144]

Answer:

Explained

Explanation:

Along some shorelines, incoming waves cause the water to simply rise and fall and not form surfs because of the steepness of the shorelines. Long period waves wont form surfs at steep shores because of the breaking and unstability of waves. Wave breaks at the shallow waters. The breaking of the waves depends upon H/L ratio.

5 0

3 years ago

A 5cm tall object is placed 4cm in front of a converging lens that has a focal length of 8cm. Where is the image located in ____

OverLord2011 [107]

Answer:

a. -8 cm

Explanation:

$d_{o}$ = distance of the object = 4 cm

$d_{i}$ = distance of the image = ?

$f$ = focal length of the converging lens = 8 cm

using the lens equation

$\frac{1}{d_{o}} + \frac{1}{d_{i}} = \frac{1}{f}$

$\frac{1}{4} + \frac{1}{d_{i}} = \frac{1}{8}$

$d_{i}$ = - 8 cm

4 0

3 years ago

Which Chinese man was leader of the National People's Party, called the Guomindang, in 1925?

Len [333]

<span>C. Mao Zedong
Hope this helps!~</span>

5 0

3 years ago

Read 2 more answers

A reasonable estimate of the moment of inertia of an ice skater spinning with her arms at her sides can be made by modeling most

Oxana [17]

Answer:

A) $I_{total}$ = 1.44 kg m², B) moment of inertia must increase

Explanation:

The moment of inertia is defined by

I = ∫ r² dm

For figures with symmetry it is tabulated, in the case of a cylinder the moment of inertia with respect to a vertical axis is

I = ½ m R²

A very useful theorem is the parallel axis theorem that states that the moment of inertia with respect to another axis parallel to the center of mass is

I = $I_{cm}$ + m D²

Let's apply these equations to our case

The moment of inertia is a scalar quantity, so we can add the moment of inertia of the body and both arms

$I_{total}$ = $I_{body}$ + 2 $I_{arm}$

$I_{body}$ = ½ M R²

The total mass is 64 kg, 1/8 corresponds to the arms and the rest to the body

M = 7/8 m total

M = 7/8 64

M = 56 kg

The mass of the arms is

m’= 1/8 m total

m’= 1/8 64

m’= 8 kg

As it has two arms the mass of each arm is half

m = ½ m ’

m = 4 kg

The arms are very thin, we will approximate them as a particle

$I_{arm}$ = M D²

Let's write the equation

$I_{total}$ = ½ M R² + 2 (m D²)

Let's calculate

$I_{total}$ = ½ 56 0.20² + 2 4 0.20²

$I_{total}$ = 1.12 + 0.32

$I_{total}$ = 1.44 kg m²

b) if you separate the arms from the body, the distance D increases quadratically, so the moment of inertia must increase

6 0

3 years ago

Question 3 of 32

Scorpion4ik [409]

Answer:

the clown can be put on a sealion and the other clown can hold a lot of peole he help a clown that was tall and heivy

Explanation:

3 0

2 years ago