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d1i1m1o1n [39]
3 years ago
14

In order to avoid heavy traffic, Antonio can drive home after working less than 7 hours or after working more than 9 hours. How

can this be written as a single compound inequality?
Mathematics
1 answer:
dmitriy555 [2]3 years ago
5 0

Answer:

h < 7 or h > 9

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Which expression is equivalent to
Nutka1998 [239]

Answer:1/5

if u do the work in ur head by adding and divide then multiplying the fractions and then divided it by 2.231 u get 1/5 on a calculator

8 0
2 years ago
Is 8.73 a rational number
djverab [1.8K]

Answer:

Yes

Step-by-step explanation:

8  73/ 100=8.73

3 0
3 years ago
Mary Beth would like to buy a more fuel-efficient vehicle instead of driving her mom's gas-guzzler. Assuming she can find a car
ozzi

Answer:

2x as much

Step-by-step explanation:

First write as an equation:

<u>3000/32*3.75 =</u>

3000/16*3.75

Then that equals:

0.5

So that means her mom's car would be half as efficent as the new one

8 0
3 years ago
This one's not too difficult, giving Brainliest and 40 points to whoever has the best answer
hjlf

15,2,31,13

Answer:

Solution given:a number that is divisible only by itself and 1 (e.g. 2, 3, 5, 7, 11).

now

all prime numbers are:

15,2,31,13

3 0
3 years ago
Read 2 more answers
In the diagram, TC represents a vertical building. The points, A and B, are on the same level as the foot C of the building such
Alenkinab [10]

Answer:

(a) The height of the building is 60.06 m

(b) The distance AB is 139.43 m

Step-by-step explanation:

The given parameters are

Given that segment BT = segment AT + 29

By trigonometric ratios, we have;

cos∠ATC = CT/AT

cos∠BTC = CT/BT

Therefore, we have;

cos(40°) = CT/AT.................................(1)

cos(56°) = CT/BT = CT/(AT + 29).....(2)

cos(56°) = CT/(AT + 29)......................(3)

From equation (1)

CT = AT×cos(40°)

From equation (3)

AT×cos(56°) + 29 × cos(56°) = CT

Therefore;

AT×cos(40°) = AT×cos(56°) + 29 × cos(56°)

AT×cos(40°) - AT×cos(56°) =  29 × cos(56°)

AT×(cos(40°) - cos(56°)) =  29 × cos(56°)

AT = 29 × cos(56°)/(cos(40°) - cos(56°)) = 78.4 m

TC = CT = AT×cos(40°) = 78.4×cos(40°) = 60.06 m

The height of the building = 60.06 m

(b) BT = AT + 29 = 78.4 m + 29 m= 107.4 m

AB = AT×sin(∠ATC ) + BT×sin(∠BTC) = 78.4×sin(40°) + 107.4×sin(56°) =  139.43 m

The distance AB =  139.43 m.

6 0
3 years ago
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