Rutherford postulated the existence of some neutral particle having mass similar to proton but there was no direct experimental evidence. Several theories and experimental observations eventually led the discovery of neutron.
Answer:
4560 Torr
Explanation:
<u>Boyle's Law</u>
where:
= initial volume
= final volume
= initial pressure
= final pressure
Given:
Substituting the given values into the formula:
To convert atm to Torr, multiply atm by 760:
I can’t see the picture here’s what I see
Answer:
Explanation:
Given that:-
![rate = k[NH_4^+][NO_2^-]](https://tex.z-dn.net/?f=rate%20%3D%20k%5BNH_4%5E%2B%5D%5BNO_2%5E-%5D)
k = 
![[NH_4^+]=0.301\ M](https://tex.z-dn.net/?f=%5BNH_4%5E%2B%5D%3D0.301%5C%20M)
![[NO_2^-]=0.160\ M](https://tex.z-dn.net/?f=%5BNO_2%5E-%5D%3D0.160%5C%20M)
So,
<u>
is the rate of the reaction at that temperature if [NH4+] = 0.301 M and [NO2−] = 0.160 M.</u>
Based on Hess's Law:
<span>2 N2(g) + 6 O2(g) + 2 H2(g) −→ 4 HNO3(l) ∆Hf = (−171.9 kJ/mol)(4 mol) </span>
<span>2 H2O(l) −→ 2 H2(g) + O2(g) ∆Hf = (-283.8 kJ/mol)(2 mol)(-1) →times -1, rxn is reversed </span>
<span>4 HNO3(l)−→ 2 N2O5(g) + 2 H2O(l) ∆Hf = (-76.4 kJ/mol)(2 mol)(-1) →times -1, rxn is reversed </span>
<span>2 N2(g) + 5 O2(g) −→ 2 N2O5(g) ∆H0 = 32.8 kJ</span>
