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damaskus [11]
3 years ago
15

The melting point of your product is 10 degrees lower than the expected one. What conclusion can you make about the purity of yo

ur product based on the melting point
Chemistry
1 answer:
DanielleElmas [232]3 years ago
5 0

Answer:

The product is significantly impure

Explanation:

In order to test for the purity of a specific sample that was synthesized, the melting point of a compound is measured. Basically speaking, the melting point identifies how pure a compound is. There are several cases that are worth noting:

  • if the measured melting point is significantly lower than theoretical, e. g., lower by 3 or more degrees, we conclude that our compound contains a substantial amount of impurities;
  • wide range in the melting point indicates impurities, unless it agrees with the theoretical range.

Since our compound is even 10 degrees Celsius lower than expected, it indicates that the compound is significantly impure.

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Help i’ll give u points
Bond [772]

Answer:

60ug

Explanation:

If it has experienced two half lives, that means it has been halved twice. in that case, to undo it, just multiply it by two twice. 0.15ug * 2 = 0.30ug. 0.30ug * 2 = 0.60ug. Hope this helps.

8 0
3 years ago
86.64 g LiBr mol LiBr
Otrada [13]

Explanation:

I don't think your question is correct, please post the right question in the comment box.

6 0
3 years ago
Read 2 more answers
How many moles of ethane gas, C2H6(g), will occupy 15.0 L at 30 degrees Celsius and 5.0 atm?
Alenkinab [10]

Answer:

3 mol

Explanation:

Given data:

Volume of ethane = 15.0 L

Temperature = 30°C

Pressure = 5.0 atm

Number of moles of ethane = ?

Solution:

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K  

T = temperature in kelvin

Now we will convert the temperature.

30+273 = 303 K

5.0 atm × 15.0 L = n×0.0821 atm.L/ mol.K   × 303 K

75 atm.L =  n× 24.87 atm.L/ mol

n = 75 atm.L / 24.87 atm.L/ mol

n = 3 mol

8 0
2 years ago
If a Geiger counter that is 1 m away from a small source reads 50 counts per minute, what will its reading be 2 m from the sourc
masya89 [10]

as the amount of radiation received is proportional to 1/d^2

2m from source


for 1m readings are 50 count per minute


for 2m =   50 / (2)^2

                   50 / 4   =  12.5 count per minute

6 0
3 years ago
Read 2 more answers
What is the mass (in grams) of 9.93 Ă— 1024 molecules of methanol (CH3OH)?
WINSTONCH [101]

Answer is: mass of methanol is 528.32 grams.

N(CH₃OH) = 9.93·10²⁴; number of methanol molecules.

n(CH₃OH) = N(CH₃OH) ÷ Na (Avogadro constant).

n(CH₃OH) = 9.93·10²⁴ ÷ 6.022·10²³ 1/mol.

n(CH₃OH) = 16.49 mol; amount of substance.

m(CH₃OH) = n(CH₃OH) · M(CH₃OH).

m(CH₃OH) = 16.49 mol · 32.04 g/mol.

m(CH₃OH) = 528.32 g.

7 0
3 years ago
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