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2 years ago

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What is the general solution to the ODE

1 answer:

Schach [20]2 years ago

5 0

we are given the ordinary differential equation of dy/dx = 2y+1. The ODE is variable separable which means x and y can be grouped altogether explicitly. In this case, the equation becomesdy / 2y + 1 = dx
1/2 ln (2y + 1) = x + ln Cln (2y + 1) = 2x + ln C2y + 1 = C e 2x y = (C e 2x - 1)/2

The ODE y' + xy = x can be grouped into y' + x(y-1) = 0 'y' / y-1 = -xThis is variable separable

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