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3 years ago

What happens to the atomic radius as the atomic number increases?

Chemistry

1 answer:

vlabodo [156]3 years ago

7 0

As the atomic number increases the atomic radius increases since it's adding more electrons to the outermost shell

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How much energy must be absorbed by 45.0g of water to increase its temperature from 83 0°C to 303.0°C?

mrs_skeptik [129]

Answer: There will be 41382 J energy must be absorbed by 45.0g of water to increase its temperature from $83.0^{o}C$ to $303.0^{o}C$ .

Explanation:

Given: Mass = 45.0 g

Initial temperature = $83.0^{o}C$

Final temperature = $303.0^{o}C$

Formula used to calculate heat energy is as follows.

$q = m \times C \times (T_{2} - T_{1})$

where,

q = heat energy

m = mass of substance

C = specific heat = $4.18 J/g^{o}C$ (here, for water)

$T_{1}$ = initial temperature

$T_{2}$ = final temperature

Substitute the values into above formula as follows.

$q = m \times C \times (T_{2} - T_{1})\\= 45.0 g \times 4.18 J/g^{o}C \times (303.0 - 83.0)^{o}C\\= 41382 J$

Thus, we can conclude that there will be 41382 J energy must be absorbed by 45.0g of water to increase its temperature from $83.0^{o}C$ to $303.0^{o}C$ .

8 0

3 years ago

Wich is not a characteristic common to all minerals

ahrayia [7]

Metallic luster is not a characteristic common to all minerals.

7 0

4 years ago

A solution of phosphoric acid was made by dissolving 10.0 g of H3PO4 in 100.0 mL of water. The resulting volume was 113 mL. Calc

rodikova [14]

Explanation:

Mass of solute = 10.0 g

mass of solvent(water) = m

Volume of solvent( water) = v = 100.0 mL

Density of water= d = $1 g/cm^3=1 g/mL$

$1 mL= 1 cm^3$

$m=d\times v=1.0 g/mL\times 100.0 = 100.0 g$

Mass of solution(M) = Mass of solute + mass of solvent

M = 10.0 g + 100.0 g = 110.0 g

Volume of the solution = V = 113 mL

Density of the solution = D

$D=\frac{M}{V}=\frac{110.0 g}{113 mL}=0.9734 g/mL$

The density of the solution is 0.9734 g/ml.

Moles of phosphoric acid = $n_1=\frac{10.0 g}{98 g/mol}=0.1020 mol$

Moles of water = $n_2=\frac{100.0 g}{18g/mol}=5.556 mol$

Mole fraction of phosphoric acid = $\chi_1$

$\chi_1=\frac{n_1}{n_1+n_2}=\frac{0.1020 mol}{0.1020 mol+5.556 mol}$

$\chi_1=0.01803$

Mole fraction of water = $\chi_2$

$\chi_2=\frac{n_2}{n_1+n_2}=\frac{5.556 mol}{0.1020 mol+5.556 mol}$

$\chi_2=0.9820$

$[Molarity]=\frac{\text{Moles of solute}}{\text{Volume of solution(L)}}$

Moles of phosphoric acid = 0.1020 mol

Volume of the solution = V = 113 mL = 0.113 L ( 1 mL = 0.001 L)

Molarity of the solution :

$=\frac{0.1020 mol}{0.113 L}=0.903 M$

$[Molality]=\frac{\text{Moles of solute}}{\text{Mass of solvent(kg)}}$

Moles of phosphoric acid = 0.1020 mol

Mass of solvent(water) = m =100.0 g = 0.100 kg ( 1 g = 0.001 kg)

Molality of the solution :

$=\frac{0.1020 mol}{0.100 kg}=1.02 mol/kg$

6 0

3 years ago

What is the magnitude of the electrostatic force between a singly charged sodium ion and an adjacent singly charged chlorine ion

Arisa [49]

To know the electrostatic force between two charges or between two ions, you can use the Coulomb's Law. The equation is F = k*q1*q1/r^2, where F is the electrostatic force, q1 and q2 are the charger for Na and Cl, and r is the distance between the centers of both atoms. In literature, the distance is 0.5 nm or 0.5 x 10^-9 meters. The charge for Na+ and Cl- is the same magnitude but different in sign. Since Na+ is a cation, its charge is +1.603x10^-19 C (the charge of an electron). For Cl- being an anion, its charge is -1.603x10^-19 C. The constant k is an empirical value equal to 9x10^9. Using the formula:

F = (9x10^9)(+1.603x10^-19)(-1.603x10^-19)/(0.5 x 10^-9)^2
F = -9.25 x 10^-10 Newtons

The negative denotes that the net force is more towards the Cl- ion.

5 0

3 years ago

What is the coefficient of oxygen (O_2) in the balanced equation for the reaction written below?

Amiraneli [1.4K]

Answer:

1 is your coefficient of oxygen

Explanation:

hope it helps

5 0

4 years ago