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Nat2105 [25]
3 years ago
15

g A laboratory analysis of an unknown compound found the following composition: C 75.68% ; H 8.80% ; O 15.52%. What is the empir

ical formula of the compound?
Chemistry
1 answer:
sammy [17]3 years ago
7 0

Answer:

THE EMPIRICAL FORMULA FOR THE UNKNOWN COMPOUND IS C7H9O

Explanation:

The empirical formula for the unknown compound can be obtained by following the processes below:

1 . Write out the percentage composition of the individual elements in the compound

C = 75.68 %

H = 8.80 %

O = 15.52 %

2. Divide the percentage composition by the atomic masses of the elements

C = 75 .68 / 12 = 6.3066

H = 8.80 / 1 = 8.8000

O = 15.52 / 16 = 0.9700

3. Divide the individual results by the lowest values

C = 6.3066 / 0.9700 = 6.5016

H = 8.8000 / 0.9700 = 9.0722

O = 0.9700 / 0.9700 = 1

4. Round up the values to the whole number

C = 7

H = 9

O = 1

5 Write out the empirical formula for the compound

C7H90

In conclusion, the empirical formula for the unknown compound is therefore C7H9O

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1 year ago
Which fact is most important in causing phospholipids to behave as they do in water?.
nevsk [136]

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Which type of mixture contains particles that are NOT spread out
umka2103 [35]

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3 0
3 years ago
At 1 atm, how much energy is required to heat 39.0 g of h2o(s at –24.0 °c to h2o(g at 121.0 °c?
earnstyle [38]
Q = mcΔt, q = energy [J] m = mass (of water) [g]; c = specific heat capacity of water [J g⁻¹ K⁻¹/°C⁻¹]; Δt = change in temperature [K/°C]
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4 0
2 years ago
Gallium is a solid metal at room temperature but melts at 29.9 °C. If you hold gallium in your hand, it melts from body heat. Ho
matrenka [14]

Answer:  4.56 Joules

Explanation:-

The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.

Q=m\times c\times \Delta T

Q = Heat absorbed = ?

m= mass of substance = 2.5 g

c = specific heat capacity = 0.372J/g^0C

Initial temperature  = T_i = 25.0°C

Final temperature  = T_f  = 29.9°C

Change in temperature ,\Delta T=T_f-T_i=(29.9-25.0)^0C=4.90^0C

Putting in the values, we get:

Q=2.5\times 0.372\times 4.90^0C

Q=4.56J

The heat absorbed by gallium must be 4.56 Joules

7 0
3 years ago
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